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Unscramble word to get list of sensible words

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Usage: $ python word=room Number of arguments: 2 arguments. Argument List: [‘’, ‘word=room’] word provided is: word=room word to unscramble is: room Number of permutations found: 12 Valid list of words: [‘room’, ‘moor’]

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Files for MakeItSense, version 1.0
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