coordinate-geometry 0.9

A project made to simplify 2D geometry

# coordinate_geometry

## Features

• Helps to perform various operations on points like calculate distance between them, write equation formed by them

• Perform various tasks in equation of lines like calculate distance between point and line , find image of point in a line etc

• find area of triangle formed by three points , incentre , circumcentre, orthocentre etc

## Important things to know about equations

• equation_type1(slope , y_intercept) –> Creates a line object with slope and y_intercept

• equation_type2(a, b, c) –> Creates a line object in form ax + by + c = 0

• equation_type3(x_intercept , y_intercept) –> Creates a line object with x_intercept and y_intercept

• equation_type4(pt:point , slope) –> Creates a line object with pt ( a point object ) and slope

• equation_type5(pt:point , pt2:point) –> Creates a line object with given two point objects , throws error if both points are same

• These types can not be used to make lines parallel to y-axis

## Examples

IMPORTS

from coordinate_geometry.point import * from coordinate_geometry.equations import * from coordinate_geometry.triangle import *

## Point

#### Distance Formula

p1=point(3,0) p2=point(0,4) print(p1.distance(p2)) # –> 5.0

#### Section Formula

Internal division

p1=point(4,4) p2=point(8,8) print(p1.section(p2,m=1,n=3)) # –> ( 5.0 , 5.0 )

External division

p1=point(4,4) p2=point(8,8) print(p1.section(p2,m=1,n=3,external=True)) # –> ( 2.0 , 2.0 )

#### Slope p1=point(1,1) p2=point(3,3) print(p1.slope(p2)) # –> 1.0

## Triangles from coordinate_geometry

A=point(0,0) B=point(5,0) C=point(5*math.cos(math.pi/3),5*math.sin(math.pi/3)) t1=Triangle(A,B,C) # NOTE : THIS IS A EQUILATERAL TRIANGLE , SO IT MUST HAVE SAME INCENTRE, ORHTOCENTRE , CENTROID and CIRCUMCENTRE print(t1.area()) # –> 10.82532 print(t1.incenter()) –> ( 2.5 , 1.4433757 ) print(t1.centroid()) –> ( 2.5 , 1.4433757 ) print(t1.circumcenter()) –> ( 2.5 , 1.4433757 ) print(t1.orthocenter()) –> ( 2.5 , 1.4433757 )

## Line

#### Solving Two Lines l1=equation_type2(a=3,b=4,c=-5) l2=equation_type2(a=3,b=-4,c=-7) print(l1.solve(l2)) # –> ( 2.0 , -0.25 )

#### Angle Between two lines

l1=equation_type5(point(1,1),point(2,2)) l2=equation_type5(point(-1,1),point(-3,3)) print(l1.slope) # –> 1.0 print(l2.slope) # –> -1.0 print(l1.angle(l2)) # –> 1.5707963267948966 (PI/2) print(l1.is_perpendicular(l2)) # –> True print(l1.is_parallel(l2)) # –> False

#### Distance Between point and line

l1=equation_type4(point(0,0),0) # X axis pt=point(3,0) pt1=point(0,3) print(l1.distance(pt)) # –> 0.0 print(l1.distance(pt1)) # –> 3.0

#### Image of a point and foot of perpendicular in a line

l1=equation_type4(point(0,0),1) pt=point(1,2) print(l1.foot_of_perpendicular(pt)) # –> ( 1.5 , 1.5 ) print(l1.image_of_point(pt)) # –> ( 2.0 , 1.0 )

## LICENSE

© 2021 Deepak Kumar Dash