django-crispy-bulma 0.1.1

Django application to add 'django-crispy-forms' layout objects for Bulma.io

django-crispy-bulma

This project is an early work in progress. You should not use this package yet, as it is poorly documented and is missing many important features. We'll remove this header when it's ready to use.

About

This is a Django application to add django-crispy-forms layout objects for Bulma. It is a fork of crispy-forms-bulma by Jure Hotujec, with the intention of adding support for Django 2.0+, as well as for components found in the bulma-extensions library.

Installation

You can install django-crispy-bulma from PyPI by running pip install django-crispy-bulma. Make sure you also have django-crispy-forms installed, as it will not work without it. In order to activate it, you'll need to modify your projects settings.py file.

First, add django-crispy-bulma to your INSTALLED_APPS:

INSTALLED_APPS = [
    'crispy_forms',
    'django_crispy_bulma',
    # ...
]

Next, add the following to the bottom of the file in order to configure crispy_forms to use the bulma template pack:

CRISPY_ALLOWED_TEMPLATE_PACKS = (
    "bootstrap",
    "uni_form",
    "bootstrap3",
    "bootstrap4",
    "bulma",
)

CRISPY_TEMPLATE_PACK = "bulma"

You may also need to use Layout objects or form objects from django_crispy_bulma in order to build certain objects, like the UploadField. See the documentation below for specifics on objects like these.

UploadField

The UploadField looks like this:

To create these with CrispyForms, you'll need both a form object and a layout object from our package. Here's an example of how to use them.

from crispy_forms.helper import FormHelper
from crispy_forms.layout import Layout
from django import forms
from django_crispy_bulma.layout import UploadField
from django_crispy_bulma.forms import ImageField, FileField

class MyForm(forms.Form):
    my_image = ImageField(
        label="Upload an image of your dog",
        required=False
    )
    my_file = FileField(
        label="Upload your actual dog in .dog format",
        required=True    
    )

    def __init__(self, *args, **kwargs):
        super().__init__(*args, **kwargs)
        self.helper = FormHelper()

        self.helper.layout = Layout(
            UploadField("my_image"),
            UploadField("my_file"),
        )

A little bit of javascript is needed in order to get the filename to display after a file upload is successful.

Written in vanilla JS, this might look something like this:

window.onload = function() {
    // Apply this to all upload fields
    const upload_fields = document.querySelectorAll(".file");
    for (let i = 0; i < upload_fields.length; i++) {
        let input = upload_fields[i].querySelector(".file-input");
        let filename = upload_fields[i].querySelector(".file-name");

        input.onchange = function() {
            filename.textContent = input.files[0].name;
        }
    }
};

For your convenience, we provide a script that handles this in our companion package, django-simple-bulma. We highly recommend you use these two packages together.