django-easy-response 1.0.0

Return HTTP responses in a easier way

settings.py

MIDDLEWARE_CLASSES = (
    ...
    # last on the list
    django_simple_response.middleware.SimpleResponseMiddleware,
)

views.py

def view(request):
    # return HTTP response with status code 200 (default)
    return

def another_view(request):
    # return HTTP response with content and status code 401
    return 401, 'Not authorized'

def yet_another_view(request):
    # return JSON/JSONP response with content and default status code
    return {'foo': 'bar'}

In a nutshell, you can either return:

1. an object, which will be serialized into the response’s content.

2. a tuple, which first element defines the status code and the second the content of the response.