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Django app to implement Bootstrap nested modals

Project description

PyPI version

Add to installed apps in settings
'bootstrap_modals',

Add to template
<script src="{% static 'django_modals/js/modals.js' %}"></script> <link rel="stylesheet" type="text/css" href="{% static 'django_modals/css/modals.css' %}"/>

Sample form and view
from crispy_forms.layout import Layout, Field   
from django_modals.forms import ModelCrispyForm  
from django_modals.view_mixins import BootstrapModelModalMixin   
from .models import User

class UserForm(ModelCrispyForm):
    class Meta:
        model = User
        fields = ['username']
        modal_title = ['Add user', 'Edit User']

    def post_init(self, *args, **kwargs):
        self.helper.layout = Layout(
            Field('username'),
            self.submit_button(css_class="btn-success"),
            self.cancel_button())

class ModalUserForm(BootstrapModelModalMixin):
    form_class = UserForm
Add modal URLS
    path('modal/user/<slug:slug>/', modals.ModalUserForm.as_view(), name='usermodal')
Generate javascript link in python
href_modal('usermodal', 'client-{}'.format(self.kwargs['pk']))
onclick_modal('usermodal', 'client-{}'.format(self.kwargs['pk']))
Adding different buttons

self.button('Delete', [{'function': 'post_modal', 'button': 'delete'}], "btn-danger")

in view the function button_buttonname will be called

def button_delete(self, request, *args, **kwargs):

The kwargs from the url are detemined in bootstrap_modals.views in split_slug

if only one item split by -  
    'pk': item
else
    'initial { even : odd }'                     

WIDGETS

Select2

In form

self.fields['field_name'].widget = Select2()`

AJAX

self.fields['field_name'].widget = Select2(attrs={'ajax': True})       

Then in view

def select2_field_name(self, request, *args, **kwargs):
    try:
        results = list(EventSubType.objects.filter(event_type_id=request.POST['field_name'])
                   .values('id').annotate(text=F('name'), value=F('id')))
    except ValueError:
        results = []
    return HttpResponse(json.dumps({'results': results}), content_type='application/json')     

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