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Easy to proxy any APIs you want.

Project description

Django Simple API Proxy

This is a simple tool for proxying any APIs easily on your Django server.

You can use it as middleware to make a layer for user authorization or something.

Installation

pip install django-simple-api-proxy

Quick Start

  1. Add django_simple_api_proxy to your INSTALLED_APPS in settings.py like this:
INSTALLED_APPS = [
...
'django_simple_api_proxy',
]
  1. Add APP settings to your settings.py like this:
TARGET_API_URL = 'https://httpbin.org'
PROXY_ROUTE_PATH = 'my_test_route'
PROXY_TARGET_PATH = ''
  1. Include the django_simple_api_proxy URL settings in your project urls.py like this:
from django.conf import settings
from django.urls import include
urlpatterns += [
    path(settings.PROXY_ROUTE_PATH, include('django_simple_api_proxy.urls'))
]
  1. Test on your server.
python manage.py runserver

Here's an example you success proxy an API by visit the following URLs.

And the result will be as below.

[06/Sep/2022 01:26:04] "GET /my_test_route/ HTTP/1.1" 200 314
2022-09-06 01:26:06.338 | DEBUG    | django_simple_api_proxy.views:get:73 - ----- Proxy GET
2022-09-06 01:26:06.339 | DEBUG    | django_simple_api_proxy.views:get_proxy_path:37 - URL: /get
2022-09-06 01:26:06.340 | DEBUG    | django_simple_api_proxy.views:update_payload:49 - Username: #anonymous
{
  "args": { "username": "#anonymous" },
  "headers": {
    "Accept": "*/*",
    "Accept-Encoding": "gzip, deflate, br",
    "Host": "httpbin.org",
    "User-Agent": "python-requests/2.27.1",
    "X-Amzn-Trace-Id": "Root=1-6316360c-2308560261599de4071127ac"
  },
  "origin": "xxx.xxx.xxx.xxx",
  "url": "https://httpbin.org/get?username=%23anonymous"
}

But when you visit http://127.0.0.1:8000/my_test_route/123, you'll get error.

Cause this URL is not found on target API server.

So, this proxy server will return this for you.

{ "status": "error" }

Usage

After the quick start, you may want to change some methods with your API server like making an authorization.

You can do it with inheriting the APIProxy class.

Here is an example:

import requests

from rest_framework.authentication import SessionAuthentication
from rest_framework_simplejwt.authentication import JWTAuthentication
from rest_framework.permissions import IsAuthenticated

from django_simple_api_proxy.views import APIProxy

class MyAPIProxy(APIProxy):
    # give custom authentication
    authentication_classes = [SessionAuthentication, JWTAuthentication]

    # give custom permission
    permission_classes = [IsAuthenticated]

    def get(self, request, *args, **kwargs):
        """Get."""
        # your new `GET` logic here

        logger.debug("----- Proxy GET Heyyaya")
        response = {"status": "default error!!"}
        try:
            params = dict(request.GET)
            path = self.get_proxy_path(request)
            params = self.update_payload(request, params)
            middle_resp_ = self.send_request("GET", path, params=params)
            response = middle_resp_.json()
        except Exception as e:
            print('yooooo error occurs!!')
            print(e)
        return self.response(response)

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