django-stapler 1.0.5.1

A package providing a multi-ModelForm solution for django

django-stapler

Provides a simple way to combine multiple ModelForm classes

Description

Django's ModelForm class lets you create a Form class for a model. This lets you conveniently create and update model instances. In some specific cases it would be desiarble to combine multiple ModelForms so that you can create and update multiple model instances in one view with one form. django-stapler provides this functionality

Dependencies

• Django 2.2+

Installing

pip install django-stapler

Basic usage

Add app to settings.py

INSTALLED_APPS = [ ...
                   'stapler',
                 ]

Define Model classes as usual

models.py

from django.db import models

# Create your models here.
class Bike(models.Model):

    name = models.CharField(max_length=10)
    frame_type = models.CharField(max_length=10, blank=True, null=True)

class Manufacturer(models.Model):

    name = models.CharField(max_length=10)
    chief = models.CharField(max_length=10)

Also declare the ModelForm classes as usual, and in addition staple the ModelForms together by creating a new StapleForm class. In the inner Meta class set the modelforms attribute to a tuple of to staple ModelForms.

forms.py

from django.forms import ModelForm
from stapler.forms import StaplerForm
from .models import Bike, Manufacturer


class BikeModelForm(ModelForm):

    class Meta:
        model = Bike
        fields = ['name', 'price']


class ManufacturerModelForm(ModelForm):

    class Meta:
        model = Manufacturer
        fields = ['name', 'revenue']

class StapledForm(StaplerForm):

    class Meta:
        modelforms = (BikeModelForm, ManufacturerModelForm)
        #auto_prefix = False, defaults is True

The StapledForm yields a form with four fields: bike__name, bike__price, manufacturer__name, manufacturer__revenue. If you want to keep the original field names, you can set the auto_prefix attribute in the Meta class to False. This may lead to unexpected behaviour when fieldnames between models clash.

You can use the StapledForm in views.py to create a new Bike and Manufacturer instance in one go by calling form.save(). This wil return a dictionary with keys resembling the Model class names in lowercase with the _instance suffix. The keys map to the newly created instances:

views.py

from django.views.generic.edit import FormView
from .forms import StapledForm

class SomeView(FormView):
    template_name = 'example.html'
    form_class = StapledForm
    success_url = '/thanks/'

    def form_valid(self, form):
        # This method is called when valid form data has been POSTed.
        # It should return an HttpResponse.
        result = form.save()
        nw_bike = result['bike_instance']   # the saved bike instance
        nw_manufacturer = result['manufacturer_instance'] # the saved manufacturer instance
        return super().form_valid(form)

You can also use the form to update existing instances by providing a tuple of instances to the named instances argument:

from .models import Bike, Manufacturer
from .forms import StapledForm

...

# inside view function
bike = Bike.objects.first()
manufacturer = Manufacturer.objects.first()

form = StapledForm(data=request.POST, instances=(bike, manufacturer))
if form.is_valid():
    result = form.save()
    result # this is a dictionary with the updated instances

StapledForm provides the pre_save and post_save hooks. These methods are called before and after the instances are saved when the save() method is called:

class StapledForm(StaplerForm):

    ...

    def pre_save(self):
        print("did you get the memo?")


    def post_save(self):
        print("have you seen my stapler?")

License

This project is licensed under the MIT License - see the LICENSE.md file for details