Mypy stubs for Django (with PR #730 merged)
Project description
pep484 stubs for Django
This package contains type stubs and a custom mypy plugin to provide more precise static types and type inference for Django framework. Django uses some Python "magic" that makes having precise types for some code patterns problematic. This is why we need this project. The final goal is to be able to get precise types for most common patterns.
Installation
pip install django-stubs
To make mypy aware of the plugin, you need to add
[mypy]
plugins =
mypy_django_plugin.main
[mypy.plugins.django-stubs]
django_settings_module = "myproject.settings"
in your mypy.ini
or setup.cfg
file.
Two things happeining here:
- We need to explicitly list our plugin to be loaded by
mypy
- Our plugin also requires
django
settings module (what you put intoDJANGO_SETTINGS_MODULE
variable) to be specified
This fully working typed boilerplate can serve you as an example.
Version compatibility
We rely on different django
and mypy
versions:
django-stubs | mypy version | django version | python version |
---|---|---|---|
1.8.0 | 0.812 | 2.2.x || 3.x | ^3.6 |
1.7.0 | 0.790 | 2.2.x || 3.x | ^3.6 |
1.6.0 | 0.780 | 2.2.x || 3.x | ^3.6 |
1.5.0 | 0.770 | 2.2.x || 3.x | ^3.6 |
1.4.0 | 0.760 | 2.2.x || 3.x | ^3.6 |
1.3.0 | 0.750 | 2.2.x || 3.x | ^3.6 |
1.2.0 | 0.730 | 2.2.x | ^3.6 |
1.1.0 | 0.720 | 2.2.x | ^3.6 |
0.12.x | old semantic analyzer (<0.711), dmypy support | 2.1.x | ^3.6 |
FAQ
Is this an official Django project?
No, it is not. We are independent from Django at the moment. There's a proposal to merge our project into the Django itself. You can show your support by liking the PR.
Is it safe to use this in production?
Yes, it is! This project does not affect your runtime at all.
It only affects mypy
type checking process.
But, it does not make any sense to use this project without mypy
.
mypy crashes when I run it with this plugin installed
Current implementation uses Django runtime to extract models information, so it will crash, if your installed apps or models.py
is not correct. For this same reason, you cannot use reveal_type
inside global scope of any Python file that will be executed for django.setup()
.
In other words, if your manage.py runserver
crashes, mypy will crash too.
You can also run mypy
with --tb
option to get extra information about the error.
I cannot use QuerySet or Manager with type annotations
You can get a TypeError: 'type' object is not subscriptable
when you will try to use QuerySet[MyModel]
, Manager[MyModel]
or some other Django-based Generic types.
This happens because these Django classes do not support __class_getitem__
magic method in runtime.
- You can go with our
django_stubs_ext
helper, that patches all the types we use as Generic in django.
Install it:
pip install django-stubs-ext # as a production dependency
And then place in your top-level settings:
import django_stubs_ext
django_stubs_ext.monkeypatch()
- You can use strings instead:
'QuerySet[MyModel]'
and'Manager[MyModel]'
, this way it will work as a type formypy
and as a regularstr
in runtime.
How can I create a HttpRequest that's guaranteed to have an authenticated user?
Django's built in HttpRequest
has the attribute user
that resolves to the type
Union[User, AnonymousUser]
where User
is the user model specified by the AUTH_USER_MODEL
setting.
If you want a HttpRequest
that you can type-annotate with where you know that the user is authenticated you can subclass the normal HttpRequest
class like so:
from django.http import HttpRequest
from my_user_app.models import MyUser
class AuthenticatedHttpRequest(HttpRequest):
user: MyUser
And then use AuthenticatedHttpRequest
instead of the standard HttpRequest
for when you know that the user is authenticated. For example in views using the @login_required
decorator.
My QuerySet methods are returning Any rather than my Model
QuerySet.as_manager()
is not currently supported.
If you are using MyQuerySet.as_manager()
, then your Manager
/QuerySet
methods will all not be linked to your model.
Example:
from django.db import models
class MyModelQuerySet(models.QuerySet):
pass
class MyModel(models.Model):
bar = models.IntegerField()
objects = MyModelQuerySet.as_manager()
def use_my_model():
foo = MyModel.objects.get(id=1) # This is `Any` but it should be `MyModel`
return foo.xyz # No error, but there should be
There is a workaround: use Manager.from_queryset
instead.
Example:
from django.db import models
class MyModelQuerySet(models.QuerySet):
pass
MyModelManager = models.Manager.from_queryset(MyModelQuerySet)
class MyModel(models.Model):
bar = models.IntegerField()
objects = MyModelManager()
def use_my_model():
foo = MyModel.objects.get(id=1)
return foo.xyz # Gives an error
Related projects
awesome-python-typing
- Awesome list of all typing-related things in Python.djangorestframework-stubs
- Stubs for Django REST Framework.pytest-mypy-plugins
-pytest
plugin that we use for testingmypy
stubs and plugins.wemake-django-template
- Create new typed Django projects in seconds.
To get help
We have Gitter here: https://gitter.im/mypy-django/Lobby If you think you have more generic typing issue, please refer to https://github.com/python/mypy and their Gitter.
Contributing
This project is open source and community driven. As such we encourage contributions big and small. You can contribute by doing any of the following:
- Contribute code (e.g. improve stubs, add plugin capabilities, write tests etc) - to do so please follow the contribution guide.
- Assist in code reviews and discussions in issues.
- Identify bugs and issues and report these
You can always also reach out in gitter to discuss your contributions!
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