Return the first true value of an iterable.
first is an MIT licensed Python package with a simple function that returns the first true value from an iterable, or None if there is none. If you need more power, you can also supply a key function that is used to judge the truth value of the element or a default value if None doesn’t fit your use case.
A simple example to get started:
>>> from first import first >>> first([0, None, False, , (), 42]) 42
However, it’s especially useful for dealing with regular expressions in if/elif/else branches:
import re from first import first re1 = re.compile('b(.*)') re2 = re.compile('a(.*)') m = first(regexp.match('abc') for regexp in [re1, re2]) if not m: print('no match!') elif m.re is re1: print('re1', m.group(1)) elif m.re is re2: print('re2', m.group(1))
The optional key function gives you even more selection power. If you want to return the first even number from a list, just do the following:
>>> from first import first >>> first([1, 1, 3, 4, 5], key=lambda x: x % 2 == 0) 4
default on the other hand allows you to specify a value that is returned if none of the elements is true:
>>> from first import first >>> first([0, None, False, , ()], default=42) 42
The package consists of one module consisting of one function:
from first import first first(iterable, default=None, key=None)
This function returns the first element of iterable that is true if key is None. If there is no true element, the value of default is returned, which is None by default.
If a callable is supplied in key, the result of key(element) is used to judge the truth value of the element, but the element itself is returned.
first has no dependencies and should work with any Python available. Of course, it works with the awesome Python 3 everybody should be using.
first brings nothing to the table that wasn’t possible before. However the existing solutions aren’t very idiomatic for such a common and simple problem.
The following constructs are equivalent to first(seq) and work since Python 2.6:
next(itertools.ifilter(None, seq), None) next(itertools.ifilter(bool, seq), None) next((x for x in seq if x), None)
None of them is as pretty as I’d like them to be. The re example from above would look like the following:
next(itertools.ifilter(None, (regexp.match('abc') for regexp in [re1, re2])), None) next((regexp.match('abc') for regexp in [re1, re2] if regexp.match('abc')), None)
Note that in the second case you have to call regexp.match() twice. For comparison, one more time the first-version:
first(regexp.match('abc') for regexp in [re1, re2])
Idiomatic, clear and readable. Pythonic. :)
The idea for first goes back to a discussion I had with Łukasz Langa about how the re example above is painful in Python. We figured such a function is missing Python, however it’s rather unlikely we’d get it in and even if, it wouldn’t get in before 3.4 anyway, which is years away as of yours truly is writing this.
So I decided to release it as a package for now. If it proves popular enough, it may even make it into Python’s stdlib in the end.
- Make installable on systems that don’t support UTF-8 by default.
- Backward incompatible: Drop support for Python older than 2.6, the previous fix gets too convoluted otherwise. Please don’t use Python < 2.6 anyway. I beg you. N.B. that this is a pure packaging/QA matter: the module still works perfectly with ancient Python versions.
predproved to be rather useless. Changed to
keywhich is just a selector. This is a backward incompatible change and the reason for going 2.0.
defaultargument which is returned instead of
Noneif no true element is found.
- Fix packaging. I get this never right the first time. :-/
- Documentation fixes only.
- Initial release.
“first” is written and maintained by Hynek Schlawack and various contributors:
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