Returns True if a string contains a variation of 'OwO'
Project description
is-furry-py
Returns True if a string contains a variation of "OwO"
Setup
- Install the module
- Use it in your code
from is_furry import evaluate
Options
Options are not currently supported in is-furry-py.
License
The project is licensed under MIT
Contributing
If you would like to contribute to this package, please read the contributing guide.
Thanks to jakobkg for improving the typings!
Support
Original Creator: Wait What#497(five)
Python Translation: Bunniico#371(6)
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is_furry_py-1.0.4.tar.gz
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