korean-word-relay 0.0.6

끝말잇기 package for python

korean-word-relay

끝말잇기 package for python

• 한국어 낱말 게임 끝말잇기를 쉽게 커스터마이징 할 수 있는 패키지
• 모델이 사용할 끝말잇기 단어 직접 선택 (난이도 조절 가능)
• 두음법칙 적용 (여부 선택)
• 이전 단어와 이어지지 않거나 이미 나왔던 단어 입력시 패배

Installation

Using pip:

pip install korean-word-relay

Usage

Quick Start

from korean_word_relay import WordRelay

word_relay = WordRelay()
word_relay.play()

result

--------------끝말잇기----------------
시작 단어: 파이썬
<< 썬샤인
>> 인간
<< 간택
>> 택시
<< 시리
>> 리그
<< 그대
>> 대략
<< 약관
>> 관람
<< 람보
>> 보도
<< 도로묵
------------------------------
no word to answer
YOU WIN!

---

Default optional parameter

word_relay = WordRelay(import_default=True, words_path=None, use_dueum=True, debug_print=True):
)

• import_default(boolean): If True, import candidates of korean words from '자주 쓰이는 한국어 낱말 모음 5800'
• words_path(None|string): If given path(.txt), import candidates of words list from txt file
• use_dueum(boolean): If True, 두음법칙 is allowed
• debug_print(boolean): If True, print warning message on console

Example format for words_path

words_path should be None or list of korean words in txt extension. For instance, word_list.txt should be

사랑
우정
믿음
.
.
여자친구

If you want to make game much difficult, get killing_words.txt from here.

---

Methods of WordRelay

word_relay = WordRelay()

# 주어진 낱말에 이어지는 단어 리턴
# set log_history=False if you don't want to add word in history
next_word = word_relay.get_next('성질') # next_word is None or 질X (예: 질문)

# 두 낱말이 이어지는지 여부 체크
is_continue = word_relay.check_continue('질문', '문지기') # is_continue == True

# 특정 낱말을 이미 나온말(history)에 추가
word_relay.add_history('문지기')
print(word_relay.history) # word_relay.history = ['질문', '문지기'], 질문 was added get_next above

# history 를 초기화
word_relay.reset()
print(word_relay.history) # word_relay.history = []

etc

Checking whether word is valid or not is not implemented in this project, since 1. criteria for valid language is keep changing, 2. including korean dictionary can make this package too big. You can implement your own code to check whether word is valid or not.