Function to get value from unknown structure
Project description
la-deep-get
Function to get value that is deep inside another structure.
install
pip install la-deep-get
syntax
dget(structure, *args, default=None)
structure
- Structure to go through
*args
- Each field to be passed as key
default
- The value to return in case it fail to access any of the keys (default is None
)
example
Let's say that you have dictionary with product information and you want all active big images.
product = {
"name": "really cool product",
"images": {
"active: {
"small": [
"https://www.smallimage.com",
"https://www.smallimage.com",
"https://www.smallimage.com",
],
"big": [
"https://www.bigimage.com",
"https://www.bigimage.com",
"https://www.bigimage.com",
]
},
"disabled": {
"small": [
"https://www.notcool.com",
"https://www.notcool.com",
"https://www.notcool.com",
],
"big": [
"https://www.notcool.com",
"https://www.notcool.com",
"https://www.notcool.com",
]
}
}
}
It's a simple one line function to get a value.
big_images = dget(product, "images", "active", "big", default=[])
Without the package you would have to do things like try except
:
try:
big_images = product["images"]["active"]["big"]
except:
big_images = []
Or chain get()
methods like:
big_images = product.get("images", {}).get("active", {}).get("big", [])
usage
All that you need to know is that you will navigate like normally do with dictionaries or lists (using square brackets) but it will not raise exceptions if one field doesn't exist along the way.
list_ = [
[1,2,3],
[4,5,6],
[7,8,9],
[
[10, 11, 12],
[13, 14, 15],
[16, 17, 18],
]
]
# Same as: list_[3][1][2]
value = dget(list_, 3, 1, 2)
print(value) # 15
list_ = {
"hello": {
"annoing": {
"dictionary": "here"
}
}
}
# Same as: list_["hello"]["annoing"]["dictionary"]
value = dget(list_, "hello", "annoing", "dictionary")
print(value) # "here"
It really doesn't care what strcuture it is.
list_ = {
"first": {
5: [
"nice"
]
}
}
# Same as: list_["first"][5][0]
value = dget(list_, "first", 5, 0)
print(value) # "nice"
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