law_dictionary 1.0.5

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You are now officially certified to include "law_dictionary" in your practice!

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law_dictionary

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description

This module checks that dictionaries provided are legit.

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install

[xonsh] pip install law_dictionary

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tutorial

The "dictionary" passed to the "check" function might be modified.
Therefore dictionary_2 = copy.deepcopy (dictionary_1) should be used if you'd like the original dictionary_1 to be preserved.

101

In this example, an obstacle is found because "directory_2" is not in the "laws"
and "allow_extra_fields" is False.

With "return_obstacle_if_not_legit" a report is returned instead of an exception
being raised.

import law_dictionary

dictionary = {
	"directory_1": "/",
	"directory_2": "/drives"
}
report = law_dictionary.check (
	return_obstacle_if_not_legit = True,
	allow_extra_fields = False,
	laws = {
		"directory_1": {
			"required": True
		}
	},
	dictionary = dictionary
)
if (report ["advance"] != True):
	raise Exception (report ["obstacle"])	

contigencies

If "required" is False, then the "contingency" value is returned or the value returned by a "contingency" function.

After "contingency" step, the "type" is checked, if "type" is passed to the "laws".

import law_dictionary

dictionary = {}

def retrieve_directory ():
	return "/"

report = law_dictionary.check (	
	return_obstacle_if_not_legit = True,
	laws = {
		"directory_1": {
			"required": False,
			"contingency": retrieve_directory,
			"type": str
		},
		"directory_2": {
			"required": False,
			"contingency": "/drives",
			"type": str
		}
	},
	dictionary = dictionary
)
if (report ["advance"] != True):
	raise Exception (report ["obstacle"])	

assert (dictionary ["directory_1"] == "/")
assert (dictionary ["directory_2"] == "/drives")

# The consequence of this check is that there are no "obstacles"
# and the dictionary is modified to have this structure:
'''
{
	"directory_1": "/",
	"directory_2": "/drives"
}
'''

allowance

The consequence of this check is that there are no "obstacles" or modifications to either dictionary.

import law_dictionary

dictionaries = [{ "directory_1": "/" }, { "directory_1": "/drives"  }]

for dictionary in dictionaries:
	law_dictionary.check (	
		laws = {
			"directory_1": {
				"required": True,
				"allow": [ "/", "/drives" ]
			}
		},
		dictionary = dictionary
	)

multiple levels

There's not a tree structure possible for multiple levels,
however after a level 1 check, level 2, etc. checks can
be run.

import law_dictionary

dictionary = { 
	"paths": {
		"directory_1": "/" 
	}
}	
	
law_dictionary.check (	
	laws = {
		"paths": {
			"required": True,
			"type": dict
		}
	},
	dictionary = dictionary
)

law_dictionary.check (	
	laws = {
		"directory_1": {
			"required": True,
			"type": str
		}
	},
	dictionary = dictionary ["paths"]
)