lazr.uri 1.0.4

A self-contained, easily reusable library for parsing, manipulating,

The lazr.uri package includes code for parsing and dealing with URIs.

>>> import lazr.uri
>>> print('VERSION:', lazr.uri.__version__)
VERSION: ...

The URI class

>>> from lazr.uri import URI
>>> uri1 = URI('http://localhost/foo/bar?123')
>>> uri2 = URI('http://localhost/foo/bar/baz')
>>> uri1.contains(uri2)
True

These next two are equivalent, so the answer should be True, even through the “outside” one is shorter than the “inside” one.

>>> uri1 = URI('http://localhost/foo/bar/')
>>> uri2 = URI('http://localhost/foo/bar')
>>> uri1.contains(uri2)
True

The next two are exactly the same. We consider a url to be inside itself.

>>> uri1 = URI('http://localhost/foo/bar/')
>>> uri2 = URI('http://localhost/foo/bar/')
>>> uri1.contains(uri2)
True

In the next case, the string of url2 starts with the string of url1. But, because url2 continues within the same path step, url2 is not inside url1.

>>> uri1 = URI('http://localhost/foo/ba')
>>> uri2 = URI('http://localhost/foo/bar')
>>> uri1.contains(uri2)
False

Here, url2 is url1 plus an extra path step. So, url2 is inside url1.

>>> uri1 = URI('http://localhost/foo/bar/')
>>> uri2 = URI('http://localhost/foo/bar/baz')
>>> uri1.contains(uri2)
True

Once the URI is parsed, its parts are accessible.

>>> uri = URI('https://fish.tree:8666/blee/blah')
>>> uri.scheme
'https'
>>> uri.host
'fish.tree'
>>> uri.port
'8666'
>>> uri.authority
'fish.tree:8666'
>>> uri.path
'/blee/blah'

>>> uri = URI('https://localhost/blee/blah')
>>> uri.scheme
'https'
>>> uri.host
'localhost'
>>> uri.port is None
True
>>> uri.authority
'localhost'
>>> uri.path
'/blee/blah'

The grammar from RFC 3986 does not allow for square brackets in the query component, but Section 3.4 does say how such delimeter characters should be handled if found in the component.

>>> uri = URI('http://www.apple.com/store?delivery=[slow]#horse+cart')
>>> uri.scheme
'http'
>>> uri.host
'www.apple.com'
>>> uri.port is None
True
>>> uri.path
'/store'
>>> uri.query
'delivery=[slow]'
>>> uri.fragment
'horse+cart'

Finding URIs in Text

lazr.uri also knows how to retrieve a list of URIs from a block of text. This is intended for uses like finding bug tracker URIs or similar.

The find_uris_in_text() function returns an iterator that yields URI objects for each URI found in the text. Note that the returned URIs have been canonicalised by the URI class:

>>> from lazr.uri import find_uris_in_text
>>> text = '''
... A list of URIs:
...  * http://localhost/a/b
...  * http://launchpad.net
...  * MAILTO:[e-mail]
...  * xmpp:[e-mail]
...  * http://bazaar.launchpad.net/%7ename12/firefox/foo
...  * http://somewhere.in/time?track=[02]#wasted-years
... '''

>>> for uri in find_uris_in_text(text):
...     print(uri)
http://localhost/a/b
http://launchpad.net/
mailto:[e-mail]
xmpp:[e-mail]
http://bazaar.launchpad.net/~name12/firefox/foo
http://somewhere.in/time?track=[02]#wasted-years

NEWS for lazr.uri

1.0.4 (2020-06-12)

• Install version.txt with package_data (Stefano Rivera, https://bugs.launchpad.net/lazr.uri/+bug/918660).

• Switch from buildout to tox.

1.0.3 (2012-01-18)

• Add compatibility with Python 3 (Thomas Kluyver).

1.0.1 (2009-06-01)

• Eliminate dependency on setuptools_bzr so sdists do not bring bzr ini, among others.

1.0 (2009-03-23)

• Initial release on PyPI