A simple interface to multiprocessing
Project description
Mantichora
A simple interface to multiprocessing
Mantichora provides a simple interface to multiprocessing.
from mantichora import mantichora
with mantichora() as mcore:
mcore.run(func1)
mcore.run(func2)
mcore.run(func3)
mcore.run(func4)
results = mcore.returns()
100.00% :::::::::::::::::::::::::::::::::::::::: | 12559 / 12559 |: func1
71.27% :::::::::::::::::::::::::::: | 28094 / 39421 |: func2
30.34% :::::::::::: | 28084 / 92558 |: func3
35.26% :::::::::::::: | 27282 / 77375 |: func4
You can simply give Mantichora as many functions as you need to run. Mantichora will run them concurrently in background processes by using multiprocessing and give you the return values of the functions. The return values are sorted in the order of the functions you have originally given to Mantichora. Progress bars from atpbar can be used in the functions.
The code in this package was originally developed in the sub-package concurrently of alphatwirl.
The examples in this file can be also run on Jupyter Notebook.
Requirement
- Python 2.7, 3.6, or 3.7
Install
You can install with conda
from conda-forge:
conda install -c conda-forge mantichora
or with pip
:
pip install -U mantichora
User guide
Quick start
I will show here how to use Mantichora by simple examples.
Import libraries
We are going use two python standard libraries
time and
random in an example
task function. In the example task function, we are also going to use
atpbar for progress bars.
Import these packages and mantichora
.
import time, random
from atpbar import atpbar
from mantichora import mantichora
Define a task function
Let us define a simple task function.
def task_loop(name, ret=None):
n = random.randint(1000, 10000)
for i in atpbar(range(n), name=name):
time.sleep(0.0001)
return ret
The task in this function is to sleep for 0.0001
seconds as many
times as the number randomly selected from between 1000
and
10000
. atpbar
is used to show a progress bar. The function takes
two arguments: name
, the label on the progress bar, and ret
, the
return value of the function.
Note: Mantichora uses multiprocessing to run task functions in background processes. As a result, task functions, their arguments, and their return values need to be picklable.
You can just try running this function without using Mantichora.
result = task_loop('task1', 'result1')
This doesn't return immediately. It waits for the function to finish. You will see a progress bar.
100.00% :::::::::::::::::::::::::::::::::::::::: | 58117 / 58117 |: task1
The return value is stored in result
.
print(result)
'result1'
Run tasks concurrently with Mantichora
Now, we run multiple tasks concurrently with Mantichora.
with mantichora(nworkers=3) as mcore:
mcore.run(task_loop, 'task', ret='result1')
mcore.run(task_loop, 'another task', ret='result2')
mcore.run(task_loop, 'still another task', ret='result3')
mcore.run(task_loop, 'yet another task', ret='result4')
mcore.run(task_loop, 'task again', ret='result5')
mcore.run(task_loop, 'more task', ret='result6')
results = mcore.returns()
In the example code above, mantichora
is initialized with an
optional argument nworkers
. The nworkers
specifies the number of
the workers. It is 3
in the above example. The default is 4
. At
most as many tasks as nworkers
can run concurrently.
The with
statement
is used in the example. This ensures that mantichora
properly
ends the workers.
You can give task functions and their arguments to mcore.run()
. You
can call mcore.run()
as many times as you need. In the above
example, mcore.run()
is called with the same task function with
different arguments. You can also use a different function each time.
mcore.run()
returns immediately; it doesn't wait for the task to
finish or even to start. In each call, mcore.run()
only puts a task
in a queue. The workers in background processes pick up tasks from the
queue and run them.
The mcore.returns()
waits until all tasks finish and returns their
return values, which are sorted in the order of the tasks you have
originally given to mcore.run()
.
Progress bars will be shown by atpbar
.
100.00% :::::::::::::::::::::::::::::::::::::::: | 1415 / 1415 |: still another task
100.00% :::::::::::::::::::::::::::::::::::::::: | 7770 / 7770 |: task again
100.00% :::::::::::::::::::::::::::::::::::::::: | 18431 / 18431 |: yet another task
100.00% :::::::::::::::::::::::::::::::::::::::: | 25641 / 25641 |: more task
100.00% :::::::::::::::::::::::::::::::::::::::: | 74669 / 74669 |: task
100.00% :::::::::::::::::::::::::::::::::::::::: | 87688 / 87688 |: another task
The results are sorted in the original order regardless of the order in which the tasks have finished.
print(results)
['result1', 'result2', 'result3', 'result4', 'result5', 'result6']
Features
Without the with
statement
end()
If you don't use the with
statement, you need to call end()
.
mcore = mantichora()
mcore.run(task_loop, 'task', ret='result1')
mcore.run(task_loop, 'another task', ret='result2')
mcore.run(task_loop, 'still another task', ret='result3')
mcore.run(task_loop, 'yet another task', ret='result4')
mcore.run(task_loop, 'task again', ret='result5')
mcore.run(task_loop, 'more task', ret='result6')
results = mcore.returns()
mcore.end()
print(results)
100.00% :::::::::::::::::::::::::::::::::::::::: | 4695 / 4695 |: yet another task
100.00% :::::::::::::::::::::::::::::::::::::::: | 7535 / 7535 |: still another task
100.00% :::::::::::::::::::::::::::::::::::::::: | 9303 / 9303 |: another task
100.00% :::::::::::::::::::::::::::::::::::::::: | 9380 / 9380 |: task
100.00% :::::::::::::::::::::::::::::::::::::::: | 5812 / 5812 |: more task
100.00% :::::::::::::::::::::::::::::::::::::::: | 9437 / 9437 |: task again
['result1', 'result2', 'result3', 'result4', 'result5', 'result6']
terminate()
mantichora
can be terminated with terminate()
. After terminate()
is called, end()
still needs to be called. In the example below,
terminate()
is called after 0.5 seconds of sleep while some tasks
are still running.
mcore = mantichora()
mcore.run(task_loop, 'task', ret='result1')
mcore.run(task_loop, 'another task', ret='result2')
mcore.run(task_loop, 'still another task', ret='result3')
mcore.run(task_loop, 'yet another task', ret='result4')
mcore.run(task_loop, 'task again', ret='result5')
mcore.run(task_loop, 'more task', ret='result6')
time.sleep(0.5)
mcore.terminate()
mcore.end()
The progress bars stop when the tasks are terminated.
100.00% :::::::::::::::::::::::::::::::::::::::: | 2402 / 2402 |: still another task
100.00% :::::::::::::::::::::::::::::::::::::::: | 3066 / 3066 |: another task
59.28% ::::::::::::::::::::::: | 2901 / 4894 |: task
69.24% ::::::::::::::::::::::::::: | 2919 / 4216 |: yet another task
0.00% | 0 / 9552 |: task again
0.00% | 0 / 4898 |: more task
Receive results as tasks finish
Instead of waiting for all tasks to finish beofre receiving the
reulsts, you can get results as tasks finish with the method
receive_one()
or receive_receive()
.
receive_one()
The method receive_one()
returns a pair of the run ID and the return
value of a task function. If no task has finished, receive_one()
waits until one task finishes. receive_one()
returns None
if no
tasks are outstanding. The method run()
returns the run ID for the
task.
with mantichora() as mcore:
runids = [ ]
runids.append(mcore.run(task_loop, 'task1', ret='result1'))
runids.append(mcore.run(task_loop, 'task2', ret='result2'))
runids.append(mcore.run(task_loop, 'task3', ret='result3'))
runids.append(mcore.run(task_loop, 'task4', ret='result4'))
runids.append(mcore.run(task_loop, 'task5', ret='result5'))
runids.append(mcore.run(task_loop, 'task6', ret='result6'))
#
pairs = [ ]
for i in range(len(runids)):
pairs.append(mcore.receive_one())
100.00% :::::::::::::::::::::::::::::::::::::::: | 1748 / 1748 |: task3
100.00% :::::::::::::::::::::::::::::::::::::::: | 4061 / 4061 |: task1
100.00% :::::::::::::::::::::::::::::::::::::::: | 2501 / 2501 |: task5
100.00% :::::::::::::::::::::::::::::::::::::::: | 2028 / 2028 |: task6
100.00% :::::::::::::::::::::::::::::::::::::::: | 8206 / 8206 |: task4
100.00% :::::::::::::::::::::::::::::::::::::::: | 9157 / 9157 |: task2
The runid
is the list of the run IDs in the order of the tasks that
have been given to run()
.
print(runids)
[0, 1, 2, 3, 4, 5]
The pairs
are in the order in which the tasks have finished.
print(pairs)
[(2, 'result3'), (0, 'result1'), (4, 'result5'), (5, 'result6'), (3, 'result4'), (1, 'result2')]
receive_finished()
The method receive_finished()
returns a list of pairs of the run ID
and the return value of finished task functions. The method
receive_finished()
doesn't wait for a task to finish. It returns an
empty list if no task has finished.
with mantichora() as mcore:
runids = [ ]
runids.append(mcore.run(task_loop, 'task1', ret='result1'))
runids.append(mcore.run(task_loop, 'task2', ret='result2'))
runids.append(mcore.run(task_loop, 'task3', ret='result3'))
runids.append(mcore.run(task_loop, 'task4', ret='result4'))
runids.append(mcore.run(task_loop, 'task5', ret='result5'))
runids.append(mcore.run(task_loop, 'task6', ret='result6'))
#
pairs = [ ]
while len(pairs) < len(runids):
pairs.extend(mcore.receive_finished())
100.00% :::::::::::::::::::::::::::::::::::::::: | 3979 / 3979 |: task3
100.00% :::::::::::::::::::::::::::::::::::::::: | 6243 / 6243 |: task2
100.00% :::::::::::::::::::::::::::::::::::::::: | 6640 / 6640 |: task1
100.00% :::::::::::::::::::::::::::::::::::::::: | 8632 / 8632 |: task4
100.00% :::::::::::::::::::::::::::::::::::::::: | 6235 / 6235 |: task5
100.00% :::::::::::::::::::::::::::::::::::::::: | 8325 / 8325 |: task6
The runid
is again the list of the run IDs in the order of the tasks
that have been given to run()
.
print(runids)
[0, 1, 2, 3, 4, 5]
The pairs
are also again in the order in which the tasks have finished.
print(pairs)
[(2, 'result3'), (1, 'result2'), (0, 'result1'), (3, 'result4'), (4, 'result5'), (5, 'result6')]
Logging
Logging in background processes is propagated to the main process in the way described in a section of Logging Cookbook.
Here is a simple example task function that uses logging
. The task
function does logging just before returning.
import logging
def task_log(name, ret=None):
n = random.randint(1000, 10000)
for i in atpbar(range(n), name=name):
time.sleep(0.0001)
logging.info('finishing "{}"'.format(name))
return ret
Set the logging stream to a string stream so that we can later retrieve the logging as a string.
import io
stream = io.StringIO()
logging.basicConfig(level=logging.INFO, stream=stream)
Run the tasks.
with mantichora() as mcore:
mcore.run(task_log, 'task1', ret='result1')
mcore.run(task_log, 'task2', ret='result2')
mcore.run(task_log, 'task3', ret='result3')
mcore.run(task_log, 'task4', ret='result4')
results = mcore.returns()
100.00% :::::::::::::::::::::::::::::::::::::::: | 4217 / 4217 |: task2
100.00% :::::::::::::::::::::::::::::::::::::::: | 7691 / 7691 |: task3
100.00% :::::::::::::::::::::::::::::::::::::::: | 8140 / 8140 |: task1
100.00% :::::::::::::::::::::::::::::::::::::::: | 9814 / 9814 |: task4
Logging made in the task function in background processes is sent to the main process and written in the string stream.
print(stream.getvalue())
INFO:root:finishing "task2"
INFO:root:finishing "task3"
INFO:root:finishing "task1"
INFO:root:finishing "task4"
License
- mantichora is licensed under the BSD license.
Contact
- Tai Sakuma - tai.sakuma@gmail.com
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