More KWARGS! Let call parameters override kwargs
Project description
More KWARGS!
Branch | Status |
---|---|
master | |
dev |
Motivation
Extensive use of dependency injection, plus managing the configuration for each of the components being injected, can result in some spectacularly complex system configuration. One way to reduce the complexity is to use configuration templates that contain useful defaults, and then overwrite the properties that need to be changed for the desired configuration.
@override
has been created to provide this templating system for Python function calls. It is mostly used for class constructors, but any method can benefit. The @overrides
decorator adds a kwargs
parameter which can be given a template of default parameters; but unlike **kwargs
, it will not raise duplicate key exceptions.
Provide default values
We decorate the login()
function with @override
. In this case, username
is a required parameter, and password
will default to None
.
@override
def login(username, password=None):
pass
Define some dicts
for use with our kwargs
parameter:
creds = {"userame": "ekyle", "password": "password123"}
alt_creds = {"username": "klahnakoski"}
The simplest case is when we use kwargs
with no overrides
login(kwargs=creds)
# SAME AS
login(**creds)
# SAME AS
login(username="ekyle", password="password123")
You may override any property in kwargs
: In this case it is password
login(password="123", kwargs=creds)
# SAME AS
login(username="ekyle", password="123")
There is no problem with overriding everything in kwargs
:
login(username="klahnakoski", password="asd213", kwargs=creds)
# SAME AS
login(username="klahnakoski", password="asd213")
You may continue to use **kwargs
; which provides a way to overlay one parameter template (creds
) with another (alt_creds
)
login(kwargs=creds, **alt_creds)
# SAME AS
login(username="klahnakoski", password="password123")
Handle too many parameters
Sometimes your method parameters come from a configuration file, or some other outside source which is outside your control. There may be more parameters than your method is willing to accept.
creds = {"username": "ekyle", "password": "password123", "port":9000}
def login(username, password=None):
print(kwargs.get("port"))
Without mo-kwargs
, passing the creds
dictionary directly to login()
would raise a key error
>>> login(**creds)
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
TypeError: login() got an unexpected keyword argument 'port'
The traditional solution is to pass the parameters explicitly:
login(username=creds.username, password=creds.password)
but that can get get tedious when done often, or the parameter list get long. mo-kwargs
allows you to pass the whole dictionary to the kwargs
parameter; only the parameters used by the method are used:
@override
def login(username, password=None):
pass
login(kwargs=creds)
# SAME AS
login(**creds)
Package all parameters
Your method can accept kwargs
as a parameter. If it does, ensure it defaults to None
so that it's not required.
@override
def login(username, password=None, kwargs=None):
print(kwargs.get("username"))
print(kwargs.get("port"))
kwargs
will always be a dict, possibly empty, with the full set of parameters. This is different from using **kwargs
which contains only the remainder of the keyword parameters.
>>> creds = {"username": "ekyle", "password": "password123", "port":9000}
>>> login(**creds)
ekyle
9000
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