pemap 0.1.1

Associates python object with other objects

pemap

Pemap is simple python library for associating ordinary python object with value. Value for object helps in performing most operations on object and getting more information on it.

Value can be used get items or sort them instead of the object directly. An object with its value forms item and multiple items forms block. Block can also be kept inside item which would result in nested blocks since block may contains another block if that item is used within block.

Value can be any python object.

Install

Enter this to your command-line application:

pip install pemap

Usage

First import pemap to use its functions

import pemap

Creates item which is combination of object with its value. Realise that value can be another type than integer or number. Value and object item can be accessed using methods.

marry_item = pemap.create_item("Marry", 30)
john_item = pemap.create_item("John", 10)
ricky_item = pemap.create_item("Ricky", 40)

marry_item.get_object() # 'Marry'
marry_item.get_value() # 30

#marry_item.set_value(20)
#marry_item.get_value() # 20

After creating items you may consider creating block object to hold the items. Block makes it easy to work with multiple items such as accessing them based on their values.

# List of items to use with block
items = [marry_item, john_item, ricky_item]
# Creates block object containing items
items_block = pemap.create_block(items)

items_block.get_values() # ['Marry', 'John', 'Ricky']
items_block.get_objects() # ['Marry', 'John', 'Ricky']

Block object contain even more methods.

It is possible to have nested blocks in that items of block contain another block. Accessing items within nested block can be hard with previous example. But it can be simple if using pemap.create_deep_block() instead of pemap.create_block() which does not take into account nested blocks.

# Create first block with items
first_block_items = [marry_item, john_item, ricky_item]
first_block = pemap.create_block(items)
# Now create item from block and give value of 300.
first_block_item = pemap.create_item(first_block, 300)

# Create item for second block
first_block_item = pemap.create_item(first_block_item)

# Create ben item and followed by second block.
# Realise that second block contains first block with items.
ben_item = pemap.create_item("Ben", 100)
second_block_items = [ben_item, first_block_item]
second_block = pemap.create_deep_block(second_block_items)

# Underlying objects from first block can be accessed in second block.
# First block has been eliminated but its items remained.
second_block.get_objects() # ['Ben', 'Marry', 'John', 'Ricky']

Block can be converted to other python objects like dictionary, tuple and value queue. This only takes into account block items excluding useful data like block value.

items = [marry_item, john_item, ricky_item]
items_block = pemap.create_block(items)

items_block.to_tuple() 
# ((10, 'John'), (30, 'Marry'), (40, 'Ricky'))
items_block.to_dict() 
# {10: 'John', 30: 'Marry', 40: 'Ricky'}
items_block.to_multi_dict() 
# {10: {'John'}, 30: {'Marry'}, 40: {'Ricky'}}

Most of block methods are available as functions ready to be used on items without creating block object.

items = [marry_item, john_item, ricky_item]
pemap.items_to_tuple(items) 
# ((10, 'John'), (30, 'Marry'), (40, 'Ricky'))
pemap.extract_objects(items)
# ['Marry', 'John', 'Ricky']

Here is example using booleans instead of numbers and it exposes few useful methods. Those methods allows getting item based wheather its value evaluates to True or False.

# Creates items with values being booleans
marry_item = pemap.create_item("Marry", True)
john_item = pemap.create_item("John", False)
ricky_item = pemap.create_item("Ricky", 0)

# Creates list with items
items = [marry_item, john_item, ricky_item]
block = pemap.create_block(items)

# Gets first item that evaluates to true.
item = block.get_true_item()
item.get_object() # "Marry"

# Gets all items evaluating to false.
items = block.get_false_items()
pemap.extract_objects(items)  # ['John', 'Ricky']

License

MIT license