peperoncino 0.0.5

peperoncino: A library for easy data processing for pandas

peperoncino: A library for easy data processing for pandas

Install

$ pip install peperoncino

How to use

Processing DataFrame

import peperoncino as pp

pipeline = pp.Pipeline(
    # query data
    pp.Query("bar <= 3"),
    # assign new feature
    pp.Assign(hoge="foo * bar"),
    # generate combination feature
    pp.Combinations(["foo", "baz"], ["*", "/"]),
    # target encoding
    pp.TargetEncoding(["baz"], "y", ref=0),
    # select features
    pp.Select(
        ["hoge", "*_foo_baz", "TARGET_ENC_baz_BY_y", "y"],
        lackable_cols=["y"],
    )
)

# execute the processing
train_df, val_df, test_df = \
    pipeline.process([train_df, val_df, test_df])

Predefined processings

name	description
ApplyColumn	Apply a function to a column.
AsCategory	Assign category dtype to columns.
Assign	Assign a feature by a formula.
Combinations	Create combination features.
DropColumns	Drop columns.
DropDuplicates	Drop duplicate rows.
Pipeline	Chain processings.
Query	Query rows by a given condition.
RenameCOlumns	Rename columns.
Select	Select columns.
StatsEncoding	Encode columns by statistical values of another column.
TargetEncoding	Target Encoding with smoothing.

Define processing

All processings are subclass of pp.BaseProcessing.
All you need is define the _process(self, dfs: List[pd.DataFrame]) -> List[pd.DataFrame] function.

class ExampleProcessing(pp.BaseProcessing):
    def _process(self, dfs: List[pd.DataFrame]) -> List[pd.DataFrame]:
        return [df + 1 for df in dfs]

If your processing doesn't depent on each other data frames, then use pp.SeparatedProcessing.

class ExampleProcessing(pp.SeparatedProcessing):
    def sep_process(self, df: pd.DataFrame) -> pd.DataFrame:
        return df * 2

If you need to merge all dataframes and then apply your processing, use pp.MergedProcessing.

class ExampleProcessing(pp.SeparatedProcessing):
    def simul_process(self, df: pd.DataFrame) -> pd.DataFrame:
        return df.assign(col1_mean=df['col1'].mean())