pipeline-integrity 1.5.1

Pipeline integrity calculation

PipelineIntegrity library

In Russian

The free, open source PipelineIntegrity library designed to calculate the degree of danger of pipeline metal loss defects according to the ASME B31G method.

Installation

pip install pipeline-integrity

Usage

A pipe under pressure, with a length, diameter and wall thickness from specified material.

from pipeline_integrity.material import Material
from pipeline_integrity.pipe import Pipe

pipe = Pipe(
  440,  # length, inches
  56,  # diameter, inches
  0.63,  # wall thickness, inches
  Material(  # pipe material
    "Steel",
    52000  # SMYS, psi
  ),
  900  # pressure, psi
)
)

Metal loss defect with a specified position on the pipe and a specified depth.

defect = pipe.add_metal_loss(
  40,  # the defect starts at a distance of 40 inches from the beginning of the pipe
  4,  # defect length 4 inches
  10,  # along the circumference of the pipe, the defect begins
       # at 10 arc minutes from the top of the pipe
  20,  # the size of the defect along the circumference is 20 arc minutes
  0.039  # defect depth 0.039 inches
)

SMTS for pipe material must be set to create context for calculating the degree of severity of the defect according to the ASME B31G method

from pipeline_integrity.method.asme.b31g_2012 import Context

pipe.material.smts = 70000
asme = Context(defect)

Defect depth less than 10% wall thickness, no danger.

assert defect.depth == 0.039
assert pipe.wallthickness == 0.63

assert asme.years() > 0
assert 0.7 < asme.erf() < 0.71

For very low pressure cases, repair is never required (special value REPAIR_NOT_REQUIRED=777).

pipe.maop = 1
assert asme.years() == asme.REPAIR_NOT_REQUIRED

The depth of the defect is 50% of the pipe wall thickness.

pipe.maop = 900
defect.depth = 0.31
assert defect.length == 4
assert 0.74 < asme.erf() < 0.75

A defect with a length of 30 inches and a depth of 50% of the pipe wall thickness requires repair at the specified working pressure in the pipe.

defect.length = 30
assert asme.years() == 0
assert asme.erf() > 1.3

When the operating pressure is reduced to a safe value, the defect does not require repair.

assert pipe.maop == 900
assert round(asme.safe_pressure, 2) == 653.71
pipe.maop = 500
asme.is_explain = True
assert asme.years() > 0

If you set context property is_explain = True, then you can get explanation in text form.

asme.explain()

Calculate ERF by ASME B31G 2012 classic.
Calculate failure stress level by the classic way.
Parameter Sflow = 1.1 * material_smys.
Sflow = 1.1 * 52000 = 57200.0.
Parameter Z = length^2 / (diameter * wallthickness).
Z = 30^2 / (56 * 0.63) = 25.51.
Parameter Z = 25.51 > 20.
Failure stress level = Sflow * (1 - depth / wallthickness).
stress_fail = 57200.0 * (1 - 0.31 / 0.63) = 29053.968.
Failure pressure = 2 * stress_fail * wallthickness / diameter.
press_fail = 2 * 29053.968 * 0.63 / 56 = 653.714.
ERF = pipe_maop / press_fail.
ERF = 500 / 653.714 = 0.765

Repair is not required at the moment, calculate the time before repair.
With corrosion rate 0.016 mm/year, pipe wall 0.63 and depth 0.31 a through hole is formed after years: 21.
Calculating the year in which the corrosion growth of the defect will require repair.
Years: 4 ERF: 0.952.
Years: 5 ERF: 1.014.
Defect will require repair after years: 4.

Development

git clone [e-mail]:vb64/pipeline.integrity.git
cd pipeline.integrity

With Python 3:

make setup PYTHON_BIN=/path/to/python3
make tests

With Python 2:

make setup2 PYTHON_BIN=/path/to/python2
make tests2

Example

Living version of online calculator example, that use this library, can be found here. The source code of this example placed in this repo in example dir.