Interfacing with message-broker functionality
Project description
posted
Interfacing with message-broker functionality
To install: pip install posted
Examples
ReactiveScope
A scope that reacts to writes by computing associated functions, themselves writing in the scope, creating a chain reaction that propagates information through the scope.
Parameters
func_nodes : Iterable[ReactiveFuncNode]
The functions that will be called when the scope is written to.scope_factory : Callable[[], MutableMapping]
A factory that returns a new scope. The scope will be cleared by calling this factory at each call to.clear()
.
Examples
First, we need some func nodes to define the reaction relationships. We'll stuff these func nodes in a DAG, for ease of use, but it's not necessary.
>>> from meshed import FuncNode, DAG
>>>
>>> def f(a, b):
... return a + b
>>> def g(a_plus_b, d):
... return a_plus_b * d
>>> f_node = FuncNode(func=f, out='a_plus_b')
>>> g_node = FuncNode(func=g, bind={'d': 'b'})
>>> d = DAG((f_node, g_node))
>>>
>>> print(d.dot_digraph_ascii())
<BLANKLINE>
a
<BLANKLINE>
│
│
▼
┌────────┐
b ──▶ │ f │
└────────┘
│ │
│ │
│ ▼
│
│ a_plus_b
│
│ │
│ │
│ ▼
│ ┌────────┐
└─────▶ │ g_ │
└────────┘
│
│
▼
<BLANKLINE>
g
<BLANKLINE>
Now we make a scope with these func nodes.
>>> s = ReactiveScope(d)
The scope starts empty (by default).
>>> s
<ReactiveScope with .scope: {}>
So if we try to access any key, we'll get a KeyError.
>>> s['g'] # doctest: +IGNORE_EXCEPTION_DETAIL
Traceback (most recent call last):
...
KeyError: 'g'
That's because we didn't put write anything in the scope yet.
But, if you give g_
enough data to be able to compute g
(namely, if you
write values of b
and a_plus_b
), then g
will automatically be computed.
>>> s['b'] = 3
>>> s['a_plus_b'] = 5
>>> s
<ReactiveScope with .scope: {'b': 3, 'a_plus_b': 5, 'g': 15}>
So now we can access g
.
>>> s['g']
15
Note though, that we first showed that g
appeared in the scope before we
explicitly asked for it. This was to show that g
was computed as a
side-effect of writing to the scope, not because we asked for it, triggering the
computation
Let's clear the scope and show that by specifying a
and b
, we get all the
other values of the network.
>>> s.clear()
>>> s
<ReactiveScope with .scope: {}>
>>> s['a'] = 3
>>> s['b'] = 4
>>> s
<ReactiveScope with .scope: {'a': 3, 'b': 4, 'a_plus_b': 7, 'g': 28}>
>>> s['g'] # (3 + 4) * 4 == 7 * 4 == 28
28
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