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create random password with varies passcode set

Project description

PasswordGenerator

PyPI version Build Status Updates

Password Generator

based on Perfect Paper Passwords

High security multifactor authentication password generator.

standard passcode set

This is the standard and conservative PPP set of 64 characters. It was chosen to remove characters that might be confused with one another. Using 4-characters per passcode, 16,777,216 passcodes are possible for very good one time password security

passcode_set = '!#%+23456789=?@ABCDEFGHJKLMNPRSTUVWXYZabcdefghijkmnopqrstuvwxyz'

example:

use standard set to create password length = 10, with 3 uppercases, 3 digits and 1 symbol

from pyPasswordGenerator import password as ps
# standard set
set = 's' 
ps.generator(length = 10, upper = 3, digits =3, symbol = 0, set =set  )
>>>'5v5njx9BAN'

visually aggressive passcode set

This is a much more "visually aggressive" (somewhat more interesting and certainly much stronger) 88-character alphabet which supports the generation of 59,969,536 possible 4-character passcodes:

passcode_set = '''!"#$%&'()*+,-./23456789:;<=>?@ABCDEFGHJKLMNOPRSTUVWXYZ[]^_abcdefghijkmnopqrstuvwxyz{|}~'''

example

use standard set to create password length = 8, with 2 uppercases, 2 digits and 2 symbol

from pyPasswordGenerator import password as ps
# visually aggressive set
set = 'v' 
ps.generator(length = 8, upper = 2, digits =2, symbol = 2, set =set  )
>>>'sX65%A^g'

use won set to limit symbol with only !#@

use your set create password length = 12, with 4 uppercases, 2 digits and 2 symbols

from pyPasswordGenerator import password as ps

# my own password set
set = '!#23456789@ABCDEFGHJKLMNPRSTUVWXYZabcdefghijkmnopqrstuvwxyz'
ps.generator(length = 11, upper = 4, digits =2, symbol = 2, set =set  )
>>>'@F8Wa#jRn6S'

Definition

Parameter Default Description
length 8 Length of Password, if length = 10 then xdat3a9$dg
upper 2 How many upper case charactors, if upper =4 GdAT3a9$Dg
digits 2 How many digits, if digits = 1 GdAT3ad$Dg
symbol 0 How many symbol if symbol=4 G#A!3a9$D!
passcode_set s v

installation

pip install pyPasswordGenerator

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