A lightweight wrapper to operate on nested dictionaries seamlessly.
Project description
Scalpl
Outline
Overview
Scalpl provides a lightweight wrapper that helps you to operate on nested dictionaries seamlessly through the built-in dict API, by using dot-separated string keys.
It’s not a drop-in replacement for your dictionnaries, just syntactic sugar to avoid this['annoying']['kind']['of']['things'] and prefer['a.different.approach'].
No conversion cost, a thin computation overhead: that’s Scalpl in a nutshell.
Benefits
There are a lot of good libraries to operate on nested dictionaries, such as Addict or Box , but if you give Scalpl a try, you will find it:
⚡ Fast
🚀 Powerful as the standard dict API
👌 Well tested
Installation
Scalpl is a Python3-only module that you can install via pip
pip3 install scalpl
Usage
Scalpl provides two classes that can wrap around your dictionaries:
LightCut: a wrapper that handles operations on nested dict.
Cut: a wrapper that handles operations on nested dict and that can cut accross list item.
Usually, you will only need to use the Cut wrapper, but if you do not need to operate through lists, you should work with the LightCut wrapper as its computation overhead is a bit smaller.
These two wrappers strictly follow the standard dict API, that means you can operate seamlessly on dict, collections.defaultdict or collections.OrderedDict.
Let’s see what it looks like with a toy dictionary ! 👇
from scalpl import Cut
data = {
'pokemons': [
{
'name': 'Bulbasaur',
'type': ['Grass', 'Poison'],
'category': 'Seed',
'ability': 'Overgrow'
},
{
'name': 'Charmander',
'type': 'Fire',
'category': 'Lizard',
'ability': 'Blaze',
},
{
'name': 'Squirtle',
'type': 'Water',
'category': 'Tiny Turtle',
'ability': 'Torrent',
}
],
'trainers': [
{
'name': 'Ash',
'hometown': 'Pallet Town'
}
]
}
# Just wrap your data, and you're ready to go deeper !
proxy = Cut(data)
You can use the built-in dict API to access its values.
proxy['pokemons[0].name']
# 'Bulbasaur'
proxy.get('pokemons[1].sex', 'Unknown')
# 'Unknown'
'trainers[0].hometown' in proxy
# True
By default, Scalpl uses dot as a key separator, but you are free to use a different character that better suits your needs.
# You just have to provide one when you wrap your data.
proxy = Cut(data, sep='->')
# Yarrr!
proxy['pokemons[0]->name']
You can also easily create or update any key/value pair.
proxy['pokemons[1].weaknesses'] = ['Ground', 'Rock', 'Water']
proxy['pokemons[1].weaknesses']
# ['Ground', 'Rock', 'Water']
proxy.update({
'trainers[0].region': 'Kanto',
})
Following its purpose in the standard API, the setdefault method allows you to create any missing dictionary when you try to access a nested key.
proxy.setdefault('pokemons[2].moves.Scratch.power', 40)
# 40
And it is still possible to iterate over your data.
proxy.items()
# [('pokemons', [...]), ('trainers', [...])]
proxy.keys()
# ['pokemons', 'trainers']
proxy.values()
# [[...], [...]]
By the way, if you have to operate on a list of dictionaries, the Cut.all method is what you are looking for.
# Let's teach these pokemons some sick moves !
for pokemon in proxy.all('pokemons'):
pokemon.setdefault('moves.Scratch.power', 40)
Also, you can remove a specific or an arbitrary key/value pair.
proxy.pop('pokemons[0].category')
# 'Seed'
proxy.popitem()
# ('trainers', [...])
del proxy['pokemons[1].type']
Because Scalpl is only a wrapper around your data, it means you can get it back at will without any conversion cost. If you use an external API that operates on dictionary, it will just work.
import json
json.dumps(proxy.data)
# "{'pokemons': [...]}"
Finally, you can retrieve a shallow copy of the inner dictionary or remove all keys.
shallow_copy = proxy.copy()
proxy.clear()
Benchmark
This humble benchmark is an attempt to give you an overview of the performances of Scalpl compared to Addict, Box and the built-in dict on Python 3.5.3.
It will summarize the number of operations per second that each library is able to perform on the JSON dump of the Python subreddit main page.
You can run this tests on your machine to see if the proportion are preserved:
python3.5 ./performance_tests.py
Here are some results
Addict:
instanciate:-------- 25,430 ops per second. get:---------------- 25,253 ops per second. get through list:--- 24,591 ops per second. set:---------------- 25,422 ops per second.
Box:
instanciate:--------- 10,037,632 ops per second. get:----------------- 2,623,730 ops per second. get through list:---- 197,536 ops per second. set:----------------- 2,428,157 ops per second. set through list:---- 201,214 ops per second.
Scalpl:
instanciate:-------- 182,837,640 ops per second. get:---------------- 27,471,923 ops per second. get through list:--- 15,867,600 ops per second. set:---------------- 27,686,668 ops per second. set through list:--- 15,670,857 ops per second.
dict:
instanciate:--------- 231,210,310 ops per second. get:----------------- 202,719,825 ops per second. get through list:---- 178,902,610 ops per second. set:----------------- 200,070,024 ops per second. set through list :--- 174,726,407 ops per second.
As a conclusion and despite being ~10 times slower than the built-in dict, Scalpl is ~10 times faster than Box on simple read/write operations, and ~100 times faster when it traverse lists. Scalpl is also ~1000 times faster than Addict.
Às a human, I make a lot of mistakes. If you find some in this humble benchmark, do not hesitate to send me an email, or fill in an issue.
Frequently Asked Questions:
- What if my keys contain dots ?
If your keys contain a lot of dots, you should use an other key separator when wrapping your data:
proxy = Cut(data, sep='->') proxy['computer->network->127.0.0.1']
Otherwise, split your key in two part:
proxy = Cut(data) proxy['computer.network']['127.0.0.1']
What if my keys contain spaces ?:
proxy = Cut(data) proxy = ['it works. perfectly fine']
License
Scalpl is released into the Public Domain. 🎉
Ps: If we meet some day, and you think this small stuff worths it, you can give me a beer, a coffee or a high-five in return: I would be really happy to share a moment with you ! 🍻
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