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Python package for strings binary classification, based on regular expressions put in a decision tree.

Project description

Basics to strtree

strtree is a Python package for strings binary classification, based on regular expressions put in a decision tree.

Github repo: stretree

With strtree you can:

  • Do a binary classification of your strings using automatically extracted regular expressions
  • Find shortest regular expressions which covers strings with positive labels in the most accurate way

Look at a quick example.

Example

Firstly, let's build a tree from strings and their labels.

import strtree


strings = ['Samsung X-500', 'Samsung SM-10', 'Samsung X-1100', 'Samsung F-10', 'Samsung X-2200',
           'AB Nokia 1', 'DG Nokia 2', 'THGF Nokia 3', 'SFSD Nokia 4', 'Nokia XG', 'Nokia YO']
labels = [1, 0, 1, 0, 1, 1, 1, 1, 1, 0, 0]

tree = StringTree()
tree.build(strings, labels, min_precision=0.75, min_token_length=1)

Let's see what regular expressions were extracted.

for leaf in tree.leaves:
    print(leaf)

# Output:
# PatternNode(".+ .+a.+", right=None, left=PatternNode(.+0.+), n_strings=11, precision=1.0, recall=0.57)
# PatternNode(".+0.+", right=None, left=None, n_strings=7, precision=1.0, recall=1.0)

You may need to check the precision and recall of the whole tree for a given set of strings and true labels.

print('Precision: {}'.format(tree.precision_score(strings, labels)))
# Precision: 1.0

print('Recall: {}'.format(tree.precision_score(strings, labels)))
# Recall: 1.0

Finally, you can pass any strings you want and see if they match to extracted regular expressions or not.

matches = tree.match(other_strings)

# You will receive a vector of the same size as other_strings containing 0's (no match) or 1's (match)

Installing

  1. Use PyPI: pip install strtree
  2. Use a distribution file located in the dist folder: pip install strtree-0.1.0-py3-none-any.whl

Contribution

You are very welcome to participate in the project. You may solve the current issues or add new functionality - it is up to you to.

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