timeit-compare 1.1.1

A method based on timeit that can help you to call timeit.timeit for several statements and provide comparison results.

timeit_compare

A method based on timeit that can help you to call timeit.timeit for several statements and provide comparison results.

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Installation

You can run the following command to install the package

pip install timeit_compare

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Usage

When using the timeit library, I am always more interested in comparing the efficiency of several different methods to solve a problem, rather than simply measuring the running time of a single statement. Here is a simple example.

from functools import reduce
from operator import add

n = 100


def sum1():
    s = 0
    i = 1
    while i <= n:
        s += i
        i += 1
    return s


def sum2():
    s = 0
    for i in range(1, n + 1):
        s += i
    return s


def sum3():
    return sum(range(1, n + 1))


def sum4():
    return reduce(add, range(1, n + 1))


def sum5():
    return (1 + n) * n // 2

The functions above are all used to sum numbers from 1 to 100, which one is the most efficient?
By using:

from timeit_compare import compare

compare(sum1, sum2, sum3, sum4, sum5)

you can easily get the results like:

The output provides detailed results, including the mean, median, minimum, maximum and standard deviation of each function's running time.

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Release Notes

Release 1.1.0

1. The results now show the time of one loop in seconds(s), milliseconds(ms), microseconds(μs), or nanoseconds(ns) instead of the total time of each repetition. The conversion relationship among time units is as follows:

   1(s) = 10^3(ms) = 10^6(μs) = 10^9(ns)
   

2. Now the compare function supports setting parameters setup and globals separately for each statement. Keyword parameters setup and globals are now used to set the default parameter values for each statement.

   from timeit_compare import compare
   
   stmt = '(1 + n) * n // 2'
   compare(
       stmt,
       (stmt, 'n = 100', {}),
       (stmt, '', {'n': 100}),
       setup='n = 100'
   )
   

3. If parameter number is not given or is less than or equal to 0, it now defaults to a value that makes the total running time not too long. You can intentionally set it to a higher value to make the results more accurate.

4. Command line calls are now supported.

   python -m timeit_compare -s "n = 100" "(1 + n) * n / 2" "sum(range(1, n + 1))"
   

   Run the following command for help.

   python -m timeit_compare -h
   

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Contact

If you have any suggestions, please contact me at [e-mail].

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