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Simple way to add a timeout to any Python code.

Project description

timeoutd

pytest Pypi Status codecov Maintainability

Installation

From PyPI:

pip install timeoutd

From source code:

git clone https://github.com/juhannc/timeoutd.git
pip install -e .

Usage

import time
import timeoutd

@timeoutd.timeout(5)
def mytest():
    print("Start")
    for i in range(1, 10):
        time.sleep(1)
        print(f"{i} seconds have passed")

if __name__ == '__main__':
    mytest()

Specify an alternate exception to raise on timeout:

import time
import timeoutd

@timeoutd.timeout(5, exception_type=StopIteration)
def mytest():
    print("Start")
    for i in range(1, 10):
        time.sleep(1)
        print(f"{i} seconds have passed")

if __name__ == '__main__':
    mytest()

You can also specify a function to be called on timeout instead of raising an exception:

import time
import timeoutd

def add_two_numbers(i: int, j: int | None = None):
    if j is None:
        j = 0
    print(f"The sum of {i = } and {j = } is {i + j}")

@timeoutd.timeout(
    5,
    on_timeout=add_two_numbers,
    on_timeout_args=(1,),
    on_timeout_kwargs={"j": 2}
)
def mytest():
    print("Start")
    for i in range(1, 10):
        time.sleep(1)
        print(f"{i} seconds have passed")

if __name__ == '__main__':
    mytest()

Multithreading

Note: This feature appears to be broken in some cases for the original timeout-decorator. Some issues might still exist in this fork.

By default, timeoutd uses signals to limit the execution time of the given function. This approach does not work if your function is executed not in a main thread (for example if it's a worker thread of the web application). There is alternative timeout strategy for this case - by using multiprocessing. To use it, just pass use_signals=False to the timeout decorator function:

import time
import timeoutd

@timeoutd.timeout(5, use_signals=False)
def mytest():
    print "Start"
    for i in range(1, 10):
        time.sleep(1)
        print("{} seconds have passed".format(i))

if __name__ == '__main__':
    mytest()

Warning: Make sure that in case of multiprocessing strategy for timeout, your function does not return objects which cannot be pickled, otherwise it will fail at marshalling it between master and child processes.

Acknowledgement

Derived from http://www.saltycrane.com/blog/2010/04/using-python-timeout-decorator-uploading-s3/, https://code.google.com/p/verse-quiz/source/browse/trunk/timeout.py, and https://github.com/pnpnpn/timeout-decorator

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