type-enforced 1.1.1

A pure python type enforcer for python type annotations

Type Enforced

A pure python (no special compiler required) type enforcer for type annotations. Enforce types in python functions and methods.

Setup

Make sure you have Python 3.9.x (or higher) installed on your system. You can download it here. For older python versions (3.7 | 3.8), you should use type_enforced==0.0.16.

• Note: Certain features are only available on newer python versions:
  • EG: Staticmethod typechecking requires python>=3.10
  • EG: Union types with | require python>=3.10

Installation

pip install type_enforced

Getting Started

type_enforcer contains a basic Enforcer wrapper that can be used to enforce many basic python typing hints. Technical Docs Here.

type_enforcer currently supports many single and multi level python types. This includes class instances and classes themselves. For example, you can force an input to be an int, a number [int, float], an instance of the self defined MyClass, or a even a vector with list[int]. Items like typing.List, typing.Dict, typing.Union and typing.Optional are supported.

You can pass union types to validate one of multiple types. For example, you could validate an input was an int or a float with [int, str], [int | float] or even typing.Union[int,str].

Nesting is allowed as long as the nested items are iterables (e.g. typing.List, dict, ...). For examle, you could validate that a list is a vector with list[int] or possibly typing.List[int].

Variables without an annotation for type are not enforced.

Supported Type Checking Features:

• Function/Method Input Typing
• Function/Method Return Typing
• All standard python types (str, list, int, dict, ...)
• Union types
  • typing.Union
  • , separated list (e.g. [int, float])
  • | separated list (e.g. [int | float])
• Nested types (e.g. dict[str] or list[int,float])
  • Note: Each parent level must be an iterable
    • Specifically a variant of list, set, tuple or dict
  • Note: dict keys are not validated, only values
  • Deeply nested types are supported too:
    • dict[dict[int]]
    • list[set[]]
• Many of the typing (package) functions including:
  • Standard generics:
    • List, Set, Dict, Tuple
  • Union
  • Optional
  • Sized
    • Essentially creates a union of:
      • list, tuple, dict, set, str, bytes, bytearray, memoryview, range
    • Note: Can not have a nested type
      • Because this does not always meet the criteria for Nested types above
  • Note: Other functions might have support, but there are not currently tests to validate them
    • Feel free to create an issue (or better yet a PR) if you want to add tests/support

Basic Usage

import type_enforced

@type_enforced.Enforcer
def my_fn(a: int , b: [int, str] =2, c: int =3) -> None:
    pass

Interactive Example

>>> import type_enforced
>>> @type_enforced.Enforcer
... def my_fn(a: int , b: [int, str] =2, c: int =3) -> None:
...     pass
...
>>> my_fn(a=1, b=2, c=3)
>>> my_fn(a=1, b='2', c=3)
>>> my_fn(a='a', b=2, c=3)
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "/home/conmak/development/personal/type_enforced/type_enforced/enforcer.py", line 85, in __call__
    self.__check_type__(assigned_vars.get(key), value, key)
  File "/home/conmak/development/personal/type_enforced/type_enforced/enforcer.py", line 107, in __check_type__
    self.__exception__(
  File "/home/conmak/development/personal/type_enforced/type_enforced/enforcer.py", line 34, in __exception__
    raise TypeError(f"({self.__fn__.__qualname__}): {message}")
TypeError: (my_fn): Type mismatch for typed variable `a`. Expected one of the following `[<class 'int'>]` but got `<class 'str'>` instead.

Nested Examples

import type_enforced
import typing

@type_enforced.Enforcer
def my_fn(
    a: dict[dict[int, float]], # Note: dict keys are not validated, only values
    b: list[typing.Set[str]] # Could also just use set
) -> None:
    return None

my_fn(a={'i':{'j':1}}, b=[{'x'}]) # Success

my_fn(a={'i':{'j':'k'}}, b=[{'x'}]) # Error:
# TypeError: (my_fn): Type mismatch for typed variable `a[i][j]`. Expected one of the following `[<class 'int'>]` but got `<class 'str'>` instead. 

Class and Method Use

Type enforcer can be applied to methods individually:

import type_enforced

class my_class:
    @type_enforced.Enforcer
    def my_fn(self, b:int):
        pass

You can also enforce all typing for all methods in a class by decorating the class itself.

import type_enforced

@type_enforced.Enforcer
class my_class:
    def my_fn(self, b:int):
        pass

    def my_other_fn(self, a: int, b: [int, str]):
      pass

You can also enforce types on staticmethods and classmethods if you are using python >= 3.10. If you are using a python version less than this, classmethods and staticmethods methods will not have their types enforced.

import type_enforced

@type_enforced.Enforcer
class my_class:
    @classmethod
    def my_fn(self, b:int):
        pass

    @staticmethod
    def my_other_fn(a: int, b: [int, str]):
      pass

Validate class instances and classes

Type enforcer can enforce class instances and classes. There are a few caveats between the two.

To enforce a class instance, simply pass the class itself as a type hint:

import type_enforced

class Foo():
    def __init__(self) -> None:
        pass

@type_enforced.Enforcer
class my_class():
    def __init__(self, object: Foo) -> None:
        self.object = object

x=my_class(Foo()) # Works great!
y=my_class(Foo) # Fails!

Notice how an initialized class instance Foo() must be passed for the enforcer to not raise an exception.

To enforce an uninitialized class object use typing.Type[classHere] on the class to enforce inputs to be an uninitialized class:

import type_enforced
import typing

class Foo():
    def __init__(self) -> None:
        pass

@type_enforced.Enforcer
class my_class():
    def __init__(self, object_class: typing.Type[Foo]) -> None:
        self.object = object_class()

y=my_class(Foo) # Works great!
x=my_class(Foo()) # Fails