Python dict with automatic and arbitrary levels of nesting along with additional utility methods.
Project description
FlexDict
Elegantly nested Python dictionaries.
Easily work with deeply nested dictionaries and write clean code using FlexDict; a small subclass of dict
. FlexDict provides automatic and arbitrary levels of nesting along with additional utility functions.
Getting Started
-
Install
pip install flexdict
-
Import
from flexdict import FlexDict
-
Create
f = FlexDict()
User's Guide
The main purpose of FlexDict
is to allow you to work with deeply nested dictionaries with minimal amount of code. It achieves this purpose by providing an automatic nesting algorithm. It can be a dangerous feature if not used with caution. That's why, FlexDict
provides some helper methods to prevent any unintentional side-effects.
Setting Items
When it comes to setting dictionary items, FlexDict
provides many options. Let's start with the most slick way:
f = FlexDict()
f['easily', 'create', 'deeply', 'nested', 'structures'] = 1
The resulting dictionary would be:
{'easily':{'create':{'deeply':{'nested':{'structures': 1}}}}
You can directly pass instances of list
, tuple
or set
instead:
f[['easily', 'create', 'deeply', 'nested', 'structures']]
f[('easily', 'create', 'deeply', 'nested', 'structures')]
f[{'easily', 'create', 'deeply', 'nested', 'structures'}]
You also have other options:
f['easily']['create']['deeply']['nested']['structures'] = 1
f.set(['easily', 'create', 'deeply', 'nested', 'structures'], 1)
f.set(('easily', 'create', 'deeply', 'nested', 'structures'), 1)
f.set({'easily', 'create', 'deeply', 'nested', 'structures'}, 1)
The resulting dictionary would be the same for all these examples. However, the set
method provides many other features. For example, you may only want to set the dictionary items if they do not already exist:
f = FlexDict({'a': {'b':1}})
f.set(['a', 'b'], 2, overwrite=False)
f.set(['a', 'c'], 2, overwrite=False)
This prevents you to overwrite existing values:
{'a': {'b': 1, 'c': 2}}
Or, if you need a counter, you can use the increment
argument to do exactly that:
f = FlexDict()
for i in range(20):
if i % 2 == 0:
f.set('Even', 1, increment=True)
else:
f.set('Odd', 1, increment=True)
f
Output:
{'Even': 10, 'Odd': 10}
(Note that overwrite
argument has no effect when increment
is enabled.)
Getting Items
Again, FlexDict
provides many alternative ways to access your dictionary items:
f = FlexDict({'key1': {'key2': {'key3': 1}}})
# 1
f['key1', 'key2', 'key3']
# 2
f['key1']['key2']['key3']
# 3
f.get(['key1', 'key2', 'key3'])
f.get(('key1', 'key2', 'key3'))
f.get({'key1', 'key2', 'key3'})
They will all return the same result:
1
There is a crucial distinction between these alternatives. Whenever you use squared brackets to access an item, FlexDict
will automatically create the keys and fill the value with an empty FlexDict
if there is no such item:
f = FlexDict()
f['a', 'b']
f
Output:
{'a': {'b': {}}}
To prevent this side-effect, FlexDict
provides two options. First one, is the get
method:
f = FlexDict()
f.get(['a', 'b']), f.get(['a', 'b'], default=0), f
The get
method returns the value provided with the default
argument if the target item does not exist:
(None, 0, {})
The other option to avoid the aformentioned side-effect is to use the recursive locking mechnasim via the lock
method. We will cover it later in this guide. However, just to give you a taste of it, the following example is added:
f = FlexDict()
f.lock()
f['a', 'b']
Output:
KeyError: 'a'
Getting the top level keys and values works just like a regular dict
:
f = FlexDict({'a': 1, 'b': 2})
f.keys(), f.values()
The only difference you would notice is f.values()
returns a list
instead of dict_values
. This is an intentional behavior since we are working with nested dictionaries:
(dict_keys(['a', 'b']), [1, 2])
You may also want to get every key and/or value inside your FlexDict
instance, even the nested ones. FlexDict
can do this with recursion:
f = FlexDict({
'a': {
'b': 1,
'c': {
'd': 1,
'e': {
'a': 3
}
}
},
'g': 4
})
f.keys(nested=True), f.values(nested=True)
This allows you to check exactly what is inside your FlexDict
instance:
(['a', 'b', 'c', 'd', 'e', 'a', 'g'], [1, 1, 3, 4])
You can even get rid of the duplicates:
f.keys(nested=True, unique=True), f.values(nested=True, unique=True)
Note that unique items gets returned inside of a set
:
({'a', 'b', 'c', 'd', 'e', 'g'}, {1, 3, 4})
If you wish, you can flatten the entire FlexDict
instance. The flatten
method returns a list
of values and their respective key-paths:
f.flatten()
Output:
[(['a', 'b'], 1), (['a', 'c', 'd'], 1), (['a', 'c', 'e', 'a'], 3), (['g'], 4)]
Last but not least, if you wish to get the last item and remove it from the FlexDict
instance, you can use the pop
method:
f = FlexDict({'a': 1, 'b': 2})
f.pop(), f
Output:
({'b': 2}, {'a': 1})
Locking & Unlocking Automatic Nesting
Like we discussed above, automatic nesting can be very dangerous in some cases. Thats why, aside from the previously mentioned workarounds, FlexDict
provides a recursive algorithm to lock and unlock this feature:
f = FlexDict()
f.lock()
f['a'] = 1 # Normal `dict` behavior works as expected
try:
f['b', 'c'] = 1 # Will throw a KeyError
except KeyError:
f.unlock()
f['b', 'c'] = 1
f
Output:
{'a': 1, 'b': {'c': 1}}
Each FlexDict
instance has an attribute called locked
which tells if it is locked. Each nested dictionary inside a FlexDict
instance is also a seperate FlexDict
instance! This means, each of them has seperate locked
attributes. The lock
method sets the locked
attribute of the specified FlexDict
instance and of all the other nested dictionaries inside of it to True
. unlock
method on the other hand, does the exact opposite. This means that you can create any hybrid lock structure you want (Do that with caution!):
f = FlexDict({'secure': {}, 'not_secure': {}})
f['secure'].lock()
f.locked, f['secure'].locked, f['not_secure'].locked
Output:
(False, True, False)
Both lock
and unlock
methods provide an argument called inplace
which allows you to create locked/unlocked copies of your FlexDict
instances:
f = FlexDict()
f_locked = f.lock(inplace=False)
f.locked, f_locked.locked
Output:
(False, True)
Other Utility Methods
You can check if your FlexDict
instance contains (is a superset of) or inside of (is a subset of) another dict
instance.
f = FlexDict({'a': {'b': 1}})
f.contains({'b': 1}), f.inside({'c': {'a': {'b': 1}}})
Output:
(True, True)
FlexDict
also allows you to easily get the length (number of keys) and size (number of keys and values) inside your dictionaries via length
and size
methods. They both utilize the previously mentioned keys
and values
methods. Hence, they can work recursively and get rid of duplicates if you wish:
f = FlexDict({
'a': {
'b': 1,
'c': {
'd': 1,
'e': {
'a': 3
}
}
},
'g': 4
})
# Can be used as a replacement for len()
print(f'Number of keys:', f.length())
print(f'Number of keys (Recursive):', f.length(nested=True))
print(f'Number of keys (Recursive, Unique):', f.length(nested=True, unique=True))
# Saves some of your time
print(f'\nNumber of items (Recursive):', f.size())
print(f'Number of items (Recursive, Unique):', f.size(unique=True))
Output:
Number of keys: 2
Number of keys (Recursive): 7
Number of keys (Recursive, Unique): 6
Number of items (Recursive): 11
Number of items (Recursive, Unique): 9
Contributing
See contributing for the details.
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