PyPI

pyipx800

Package Python pour contrôler le module IPX800v4 de GCE-Electronics.

Utilisation

from pyipx800 import pyipx800

ipx = pyipx800.pyipx800("ipx800_v4", 80, "apikey")
ipx.configure()

d1 = ipx.inputs[0]
print("Input %d : <%s> = %d" % (d1.id, d1.name, d1.state))

License Information

READ LICENSE FILE

License
- OSI Approved :: MIT License
Operating System
- OS Independent
Programming Language
- Python :: 3

Metadata

License
- OSI Approved :: MIT License
Operating System
- OS Independent
Programming Language
- Python :: 3

Release files for pyipx800 0.0.3

For a detailed explanation of source distributions (sdists) and built distributions (wheels), please see the package formats documentation.

Source distribution (sdist)

Source distribution for pyipx800 0.0.3
File	Size	Uploaded
pyipx800-0.0.3.tar.gz	3.6 kB	Mar 25, 2020	Details

Release files / pyipx800-0.0.3.tar.gz

Download URL	pyipx800-0.0.3.tar.gz
Size	3.6 kB
Tags	Source
SHA-256 checksum How to use checksums	`6d52daac825b7b504a3b1feaea9e79c0dc2d9b577836a9e7ce9397b015d26ff9`
BLAKE2b-256 checksum How to use checksums	`ac1eb572ed3182c1cc841f7590f4acafe93aeb51ec275975df8afa454fddfb11`
Upload date	Mar 25, 2020
Uploaded using Trusted Publishing? What is trusted publishing?	No
Uploaded via	`twine/3.1.1 pkginfo/1.5.0.1 requests/2.23.0 setuptools/41.2.0 requests-toolbelt/0.9.1 tqdm/4.43.0 CPython/3.7.7`