Python [scrypt][] bindings
This is a set of [Python][] bindings for the [scrypt][] key derivation function.
Scrypt is useful when encrypting password as it is possible to specify a minimum amount of time to use when encrypting and decrypting. If, for example, a password takes 0.05 seconds to verify, a user won’t notice the slight delay when signing in, but doing a brute force search of several billion passwords will take a considerable amount of time. This is in contrast to more traditional hash functions such as MD5 or the SHA family which can be implemented extremely fast on cheap hardware.
Installation
$ hg clone http://bitbucket.org/mhallin/py-scrypt $ cd py-scrypt $ python setup.py build
Become superuser (or use virtualenv): # python setup.py install
Run tests after install: $ python tests/scrypt-tests.py
If you want py-scrypt for your Python 3 environment, just run the above commands with your Python 3 interpreter. Py-scrypt supports both Python 2 and 3.
Usage
The bindings are very simple – there is an encrypt and a decrypt method on the scrypt module:
>>> import scrypt
>>> data = scrypt.encrypt('a secret message', 'password', maxtime=0.1) # This will take at least 0.1 seconds
>>> data[:20]
'scrypt\x00\r\x00\x00\x00\x08\x00\x00\x00\x01RX9H'
>>> scrypt.decrypt(data, 'password', maxtime=0.1) # This will also take at least 0.1 seconds
'a secret message'
>>> scrypt.decrypt(data, 'password', maxtime=0.05) # scrypt won't be able to decrypt this data fast enough
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
scrypt.error: decrypting file would take too long
>>> scrypt.decrypt(data, 'wrong password', maxtime=0.1) # scrypt will throw an exception if the password is incorrect
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
scrypt.error: password is incorrect
From these, one can make a simple password verifier using the following functions:
- def randstr(length):
return ‘’.join(chr(random.randint(0,255)) for i in range(length))
- def hash_password(password, maxtime=0.5, datalength=64):
return scrypt.encrypt(randstr(datalength), password, maxtime=maxtime)
- def verify_password(hashed_password, guessed_password, maxtime=0.5):
- try:
scrypt.decrypt(hashed_password, guessed_password, maxtime) return True
- except scrypt.error:
return False
Acknowledgements
[Scrypt][] was created by Colin Percival and is licensed as 2-clause BSD. Since scrypt does not normally build as a shared library, I have included the source for the currently latest version of the library in this repository. When a new version arrives, I will update these sources.
[Burstaholic][] on Bitbucket provided the necessary changes to make the library build on Windows.
License
This library is licensed under the same license as scrypt; 2-clause BSD.
[scrypt]: http://www.tarsnap.com/scrypt.html [Python]: http://python.org [Burstaholic]: https://bitbucket.org/Burstaholic
Metadata
Release files for scrypt 0.5.4
For a detailed explanation of source distributions (sdists) and built distributions (wheels), please see the package formats documentation.
Source distribution (sdist)
| File | Size | Uploaded | Provenance | Actions |
|---|---|---|---|---|
| scrypt-0.5.4.tar.gz | 21.5 kB | Without provenance | Details for scrypt-0.5.4.tar.gz |
Release files / scrypt-0.5.4.tar.gz
| Download URL | scrypt-0.5.4.tar.gz |
|---|---|
| Size | 21.5 kB |
| Tags | Source |
|
SHA-256 checksum How to use checksums |
0c822b5d69616b6ebdb45ae4adb8e14792bb13bb53d150578e6291adc2b67b06
|
|
BLAKE2b-256 checksum How to use checksums |
e30851883438fdec332a7c99be3d1251c38b38038e3a1959bf92a987b5122245
|
| Upload date | |
|
Uploaded using Trusted Publishing? What is trusted publishing? |
No |
Security for scrypt 0.5.4
Provenance
Provenance describes where a file came from. On PyPI, provenance is shared via attestations, which provide a verifiable record of the build or publishing details. View details, limitations and caveats.
No provenance found
None of the files in this release were uploaded with provenance metadata.
A note on package security
PyPI is a repository for distributing packages, not a service for auditing them. While third-party security researchers and our staff do their best to detect and remove malicious packages, PyPI cannot guarantee the quality, security or suitability of any given package.
To learn more about protecting yourself from malicious actors, visit our package security documentation.