Based on the timeit library, timeit_compare can time multiple statements and provide comparison results.
Project description
timeit_compare
Based on the timeit library, timeit_compare can time multiple statements and provide comparison results.
Installation
You can run the following command to install the package.
pip install timeit_compare
Usage
When using the timeit library, I am always more interested in comparing the efficiency of several different methods to solve a problem, rather than simply measuring the running time of a single statement. Here is a simple example.
from functools import reduce
from operator import add
n = 100
def sum1():
s = 0
i = 1
while i <= n:
s += i
i += 1
return s
def sum2():
s = 0
for i in range(1, n + 1):
s += i
return s
def sum3():
return sum(range(1, n + 1))
def sum4():
return reduce(add, range(1, n + 1))
def sum5():
return (1 + n) * n // 2
The functions above are all used to sum numbers from 1 to 100, which one is the
most efficient?
By using:
from timeit_compare import compare
compare(sum1, sum2, sum3, sum4, sum5)
you can easily get the results like:
The output provides detailed results, including the mean, median, minimum, maximum and standard deviation of each function's running time.
You can also perform the following operations to obtain specific values:
from timeit_compare import Compare
cmp = Compare()
for func in sum1, sum2, sum3, sum4, sum5:
cmp.add_timer(func)
cmp.run()
# cmp.print_results()
result = cmp.get_result(0) # get the result of the timer with index 0
print(
result.time, result.repeat, result.number,
result.mean, result.median, result.min, result.max, result.std,
result.error, sep='\n'
)
# [3.3324892420678126e-06, 3.175742677501652e-06, 3.2153616044376503e-06, 3.267199346172507e-06, 3.2638434747711383e-06]
# 5
# 24405
# 3.2509272689901518e-06
# 3.2638434747711383e-06
# 3.175742677501652e-06
# 3.3324892420678126e-06
# 5.916418598334957e-08
# None
fastest = cmp.get_fastest() # get the result of the fastest timer
print(fastest.index) # 4
In a command line interface, call as follows:
python -m timeit_compare -s "n = 100" "s = 0;for i in range(1, n + 1):; s += i" "sum(range(1, n + 1))" "(1 + n) * n // 2"
Run the following command for help:
python -m timeit_compare -h
Contact
If you have any suggestions, please contact me at 23S112099@stu.hit.edu.cn.
End
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