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Timedelta for business time. Supports exact amounts of time (hours, seconds), custom schedules, holidays, and time zones.

Project description

BusinessTimeDelta

Python's timedelta for business time. This module helps you calculate the exact working time between two datetimes. It supports common scenarios such as custom schedules, holidays, and time zones.

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Installation

Use pip to install BusinessTimeDelta.

pip install businesstimedelta

Example Use

Define your business hours

import datetime
import pytz
import businesstimedelta

# Define a working day
workday = businesstimedelta.WorkDayRule(
    start_time=datetime.time(9),
    end_time=datetime.time(18),
    working_days=[0, 1, 2, 3, 4])

# Take out the lunch break
lunchbreak = businesstimedelta.LunchTimeRule(
    start_time=datetime.time(12),
    end_time=datetime.time(13),
    working_days=[0, 1, 2, 3, 4])

# Combine the two
businesshrs = businesstimedelta.Rules([workday, lunchbreak])

Calculate the business time between two datetimes

start = datetime.datetime(2016, 1, 18, 9, 0, 0)
end = datetime.datetime(2016, 1, 22, 18, 0, 0)
bdiff = businesshrs.difference(start, end)

print bdiff
# <BusinessTimeDelta 40 hours 0 seconds>

print "%s hours and %s seconds" % (bdiff.hours, bdiff.seconds)
# 40 hours and 0 seconds

Business time arithmetic

print start + businesstimedelta.BusinessTimeDelta(businesshrs, hours=40)
# 2016-01-22 18:00:00+00:00

print end - businesstimedelta.BusinessTimeDelta(businesshrs, hours=40)
# 2016-01-18 09:00:00+00:00

To define holidays, simply use the Holidays package

import holidays as pyholidays

ca_holidays = pyholidays.US(state='CA')
holidays = businesstimedelta.HolidayRule(ca_holidays)
businesshrs = businesstimedelta.Rules([workday, lunchbreak, holidays])

# Christmas is on Friday 2015/12/25
start = datetime.datetime(2015, 12, 21, 9, 0, 0)
end = datetime.datetime(2015, 12, 28, 9, 0, 0)
print businesshrs.difference(start, end)
# <BusinessTimeDelta 32 hours 0 seconds>

Timezones

If your datetimes are not timezone aware, they will be localized to UTC (see example above).

Let's say you want to calculate the business time overlap between a working day in San Francisco and in Santiago, Chile:

santiago_workday = businesstimedelta.WorkDayRule(
    start_time=datetime.time(9),
    end_time=datetime.time(18),
    working_days=[0, 1, 2, 3, 4],
    tz=pytz.timezone('America/Santiago'))

santiago_lunchbreak = businesstimedelta.LunchTimeRule(
    start_time=datetime.time(12),
    end_time=datetime.time(13),
    working_days=[0, 1, 2, 3, 4],
    tz=pytz.timezone('America/Santiago'))

santiago_businesshrs = businesstimedelta.Rules([santiago_workday, santiago_lunchbreak])

sf_tz = pytz.timezone('America/Los_Angeles')
sf_start = sf_tz.localize(datetime.datetime(2016, 1, 18, 9, 0, 0))
sf_end = sf_tz.localize(datetime.datetime(2016, 1, 18, 18, 0, 0))

print santiago_businesshrs.difference(sf_start, sf_end)
# <BusinessTimeDelta 4 hours 0 seconds>

Overnight Shifts

# Day shift
workday = WorkDayRule(
    start_time=datetime.time(9),
    end_time=datetime.time(17),
    working_days=[0, 1, 2, 3, 4],
    tz=pytz.utc)

# Night shift
nightshift = businesstimedelta.WorkDayRule(
    start_time=datetime.time(23),
    end_time=datetime.time(7),
    working_days=[0, 1, 2, 3, 4])

businesshrs = businesstimedelta.Rules([workday, nightshift])

start = datetime.datetime(2016, 1, 18, 9, 0, 0)
end = datetime.datetime(2016, 1, 22, 18, 0, 0)
bdiff = businesshrs.difference(start, end)

print bdiff
# <BusinessTimeDelta 80 hours 0 seconds>

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