countertype-sp 0.1.6

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counttypes

Count types in a list - int, float, str, bool, list, set, dict, tuple

Example

from countertypes import counterTypes

data = [1, 2.2, 'hello', [1, 2], {'a': 1},  9, 18, {'a': 4}, {'a': 1}, [1, 15, 0, 8], (1, 8), 9, (89, 9), False, True]
counter = counterTypes(data)

# check non zero datatype present inside list
print(counter.NonZeroTotal())

# sum of all datatype
print(counter.listSum('bool'))

# get a list of all datatypes
print(counter.lstOfBool)

# get a max datatype
print(counter.getMaxDataType())

# get a min datatype
print(counter.getMinDataType())

# get all datatypes count in dict form
print(counter.getCount())

# get all datatype list, in dict form
print(counter.get())

# sum of all (int, float, bool) list
print(counter.sumOfNumeric())

# get all (int, float, bool, string) in string form, inside a dict
print(counter.stringifyAll())

# get seccond to finish, the program
a1 = counterTypes.start()
print(counterTypes.end(a1))

# get a particular object convert into string
print(counter.stringFy())

# convert a object into JSON formate
JSON_Text = counter.JSON()
print(JSON_Text)

# Convert a JSON formate into Python Code
print(counterTypes.UnJSON(JSON_Text))
statusOne = "`('Hi',  'I', 'am',  'Suresh')`"
print(counterTypes.UnJSON(statusOne))

#  compare each element inside 2 list with same len
value1 = counter.lstOfInt
lst = [1, 4, 5, 4.5]
print(counterTypes.compareEachElement(value1, lst))

# reversing a list, when reverse=True
print(counter.reverse())


lst = ['1.2', '3', '9.0', '10', 'suresh', '18', 'Bool', 'True']
counter1 = counterTypes(lst)
# convert a string into (int or float), if data in numeric form.
counterOneData = counter1.numeriFy()
print(counterOneData)


counterTwoData = counterTypes(counterOneData)
# convert a string to "bool", by default value is "True" and "False". 
# use can set a key to convert a real data into bool value if key is exist inside list
print(counterTwoData.booliFy(condition=True, FalseKey=3))

# get value in order (int, float, bool, string, list, tuple, set, dict). if key=flase
# if key=True, then you can get a list carring a dict of all datatype list value. like get()
print(counterTwoData.formatic(key=True))

# find a value inside a list
print(counterTwoData.find(key=0))

# get a count of value inside list
print(counterTwoData.count(key=3))

# replace a old element with new element
print(counterTwoData.replace(re=3, key=10))

# remove a element if exist
print(counterTwoData.remove(key=3))

lst = [[1,2, [3, 4], [10, 1], [10, [0, 9], [0, 8]], [90]]]
counterThreeData = counterTypes(lst)

# convert a nested list into a single list form
print(counterThreeData.oneList())

# divide a list into a pair
print(counterTwoData.chunks(pair=3))

# get a list of table, by default it gives for table 2, but change table using "key=table" and set "end=On"
print(counterTypes.TableList(key=40, end=19))

# printing table, in table formate "2 x 1 = 2", no need to use print, set "key" and "end"
counterTypes.Table()

# find a element location
# nested_data = [[1, 2], [4, 5, [6, [7], 8]]]
nested_data = [{'name' : 'suresh', 'no' : 9820646838},[1, 0, (22, 8), 0], 7]
target_value = 'name'

counter = counterTypes(nested_data)
location = counter.find_location(target_value)

if location:
    print(f"Value {target_value} found at path: {location}")
else:
    print(f"Value {target_value} not found.")