cubik 0.3.1

Fast Rubik's Cube engine with Python bindings

Cubik

Python module, backended by C++ via SWIG, for emulating a Rubik's cube and its behaviors for implementing solving algorithms, search algorithms, and more.

Usage

Installation

To install simply run: pip install cubik

Creating a Cube

from cubik import Cube

cube = Cube()
print(cube)

Outputs:

      ⬜⬜⬜            
      ⬜⬜⬜            
      ⬜⬜⬜            
🟧🟧🟧🟩🟩🟩🟥🟥🟥🟦🟦🟦
🟧🟧🟧🟩🟩🟩🟥🟥🟥🟦🟦🟦
🟧🟧🟧🟩🟩🟩🟥🟥🟥🟦🟦🟦
      🟨🟨🟨            
      🟨🟨🟨            
      🟨🟨🟨    

Applying a Move

cube_R = cube.R() # applies R move

Note: all move methods return a new cube This means that cube will be unchanged and cube_R is the result of applying a 'R' move to cube.

Applying a Sequence of Moves

from cubik import Cube, Moves

cube = Cube()

checker_moves = [Moves.M2, Moves.E2, Moves.S2] # sequence of moves to build a checker pattern on the cube

checkered_cube = cube.apply_moves(checker_moves)

Outputs:

      ⬜🟨⬜            
      🟨⬜🟨            
      ⬜🟨⬜            
🟧🟥🟧🟩🟦🟩🟥🟧🟥🟦🟩🟦
🟥🟧🟥🟦🟩🟦🟧🟥🟧🟩🟦🟩
🟧🟥🟧🟩🟦🟩🟥🟧🟥🟦🟩🟦
      🟨⬜🟨            
      ⬜🟨⬜            
      🟨⬜🟨   

A Few Other Handy Functions and Features

cube.is_solved() # returns true if the cube is solved, false otherwise
cube.get_state() # returns a tuple of 6 elements 

other_cube = cube()
other_cube == cube # true as both cubes are in equal states
other_cube.R() == cube.R() # ditto

other_cube != cube.R() # true because other_cube is not the as cube+R

canon = cube.cannonical() # returns a cube in canonical orientation*

cube.is_valid_state() # returns true if cube is in a solvable state

* cannonical orientation is green in front, white on top, red on right, etc.

Rubik's Cube Notation

For cube notation please refer to 3x3 Rubik's Cube Move Notation.

The Backend

Each face is represented as a uint32_t and each color is represented by a 3-bit section of the uint32_t. This means the entire represntation the cube only takes up $6*32=192$ bits or $24$ Bytes!!

Specifically:

Sticker	Bits
Top Left	$(b_0,b_1,b_2)$
Top Middle	$(b_3,b_4,b_5)$
Top Right	$(b_6,b_7,b_8)$
Middle Left	$(b_9,b_{10},b_{11})$
Center	$(b_{12},b_{13},b_{14})$
Middle Right	$(b_{15},b_{16},b_{17})$
Bottom Left	$(b_{18},b_{19},b_{20})$
Bottom Middle	$(b_{21},b_{22},b_{23})$
Bottom Right	$(b_{24},b_{25},b_{26})$

* where b0 is the least significant bit.