ddn 1.0.1

DictDefaultNone. Get data from nested lists and dictionaries use simple syntax(eg.: dict1["k1"]["k2"][0]["k"]), if can‘t return None, no raise error

DictDefaultNone

Get data from nested lists and dictionaries use Simple syntax, if can‘t return None, no raise IndexError or KeyError 用简单的python语法快速获取嵌套列表或者字典里的数据，如果没取到则返回空，而不是抛出IndexError或者KeyError

eg.: dict1["k1"]["k2"][0]["k"]

from ddn import DDN

data = {
    "data": [
        {
            "key1": "123",
            "key2": {
                "kkey1": {
                    "kkkey1": "1234",
                    "kkkey2": 12345
                }
            }
        },
        {
            "key1": "'1234'",
            "key3": {
                "kkey1": {
                    "kkkey1": "1234",
                    "kkkey2": True
                }
            }
        }
    ]
}

d = DDN(data)

if res1 := d['data'][1]["key3"]["kkey1"]['kkkey1']:  # '1234'
    print('ok', res1)
if not (res2 := d['data'][88]["user"]["username"]['firstname']):  # ''
    print('no', res2 + '1234')

print(DDN({13: 1}) + {23: 4})  # {13: 1, 23: 4}
print(DDN({13: 1}) + '123123', type(DDN({13: 1}) + '123123'))  # {13: 1}123123 <class 'str'>