easySED 0.1

This module to used to add military level encryption system to your project

Easy Secure Encryptor Decryptor module

This module to used to add military level encryption system to your project

Main Users : Hunders of security oriented applications

install module using pip command

pip install easySED

To import in project -

from easySED import SED

Then make a object instance of ED class

obj = SED.ED()

How this algorithm works

generates a random key of length 44 length

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        ++

Takes and password and salt to with the pin provided (123456 is used if not provided) Salting works with this function

count = 0

newPass = passwordProvided

for i in pinProvided:
   digit = int(i)
   newPass = newPass[:digit] + self.saltList[count] + newPass[digit:]
   count += 1

return newPass

Salt list is setted by default - ["This" , "is" , "an" , "industry" , "level" , "encryption"]

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Then we encrypt this key using the world class one time pad crytography This is encrypted by key which is returnedNewpass + keySalt (by default = "harshnative)

then we encrypt the thing using the key and add it to encrypted key

and done

How secure is this

if you change all the salt list , pin , set a 12 digit pass , set security level to high , and keysalt then this encypted string should be unbreakable by any super computer in the world at least in a persons life time

Methods -

obj.setPassword_Pin_keySalt(password , pin = 123456 , keySalt = "harshnative")

By default security level is set to high , so you have to pass the password containing all lower case , upper case , nums , special character else it will raise error

to remove this you have to set security level to low

obj.setSecurityLevel_toLow()     # not recommended

Also is it recommend that you deallocate the password from your script by del operator

2. you can also set your own salt list

obj.setOwnSaltList(saltListPass)

Remember length of the list must be 6

3. if you want to output the password in the encrypted form so that the decryptor can tell if it can decrypt the string correctly or not the you have to call this function

remember - avoid this were ever possible , as it makes the things less secure

obj.setOutPutPass()

4. you can chech whether the string an be decrypted or not

obj.canDecrypt()

return True or false

or returns None if password was provided in the encrypted string

encrypting

after setting the password and optional things like keysalt , pin , saltlist etc call this method and pass on the string to be encrypted here

obj.encrypter(passStringHere)

decrypting

after setting the password and optional things like keysalt , pin , saltlist etc call this method and pass on the ecnrypted string here

obj.decrypter(passStringHere)

raise error if fails to decypt the things

Sample program -

from easySED import SED

e = SED.ED()

saltList = ["hello" , "is" , "an" , "my" , "level" , "encryption"]

e.setSecurityLevel_toLow()
e.setPassword_Pin_keySalt("#123" , "236598" , "letscodeofficial.com")
e.setOwnSaltList(saltList)

encoded  = e.encrypter("helloBoi")
print(encoded)
print(e.canDecrypt(encoded))
decoded = e.decrypter(encoded)
print(decoded)

# output - 

# 1b01192129380d23225231202e060b0d16350c1950753c0e005a02113d060b5f3c3505280a31322a1c3d5151gAAAAABfZzh-TaV4qNffIN7eu94lfzueGuIf_pcLr_BWhGkwTUAJm9DcCY5xq-Gj3k2FtysNPI0NjZZkS6YGyx6CCMww2A0g3Q==
# None
# helloBoi

Contibute -

Post any issues on github

Check out code on github