equation-maths-helper 1.5

ENG: A module that allows you to solve quadratic and linear equations. | RU: Модуль, позволяющий решать квадратные и линейные уравнения.

equation_maths_helper

ENG

A module that allows you to solve quadratic and linear equations.

How to use?

Importing

First, import the equation class from the equation_math_helper module.

from equation_maths_helper import equation

The linear_one_variable method

The linear_one_variable method allows you to solve linear equations with a single variable.

The method accepts the coefficients a and b from the formula ax + b = 0. It also has an additional solution parameter, which is responsible for outputting a step-by-step solution to the console. By default it is set to False. The method returns False if it fails (there are no roots), the root of the equation, or True if the root is any number.

Example of using the method:

from equation_maths_helper import equation
equation_answer = equation().linear_one_variable(a=1, b=1, solution=True)
print(equation_answer)

Output the solution to the console:

Root: x = -b / a = x = 1 / 1 = 1.0.
1.0

The quadratic method

The quadratic method allows you to solve quadratic equations.

The method accepts the coefficients a, b, and c from the formula a(x ** 2) + bx + c = 0. It also has an additional parameter solution, which is responsible for displaying the step-by-step solution on the console. By default, it is set to False. The method returns False if it fails (no roots) or a tuple with 1 or 2 roots of the equation.

An example of using the method:

from equation_maths_helper import equation
equation_answer = equation().quadratic(a=1, b=-5, c=6, solution=True)
print(equation_answer)

Output of the solution to the console:

Discriminant: (b ** 2) - 4 * a * c = (-5 ** 2) - 4 * 1 * 6 = 1.
First root: x1 = (-b - sqrt(d)) / 2 * a = (5 - 1.0) / 2 * 1 = 2.0.
Second root: x2 = (-b + sqrt(d)) / 2 * a = (5 + 1.0) / 2 * 1 = 3.0.
Roots: 2.0, 3.0.
(2.0, 3.0)