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ferrotherm

Thermodynamic computing from Python: state a problem, get named values back.

The physics is open and old — Ising (1925), Glauber dynamics (1963), Gibbs sampling (Geman & Geman 1984) — and a "thermodynamic sampling unit" accelerates exactly these loops. This package binds the ferrotherm Rust library through its C ABI: the solver is zero-dependency Rust, deterministic by seed, verified against exact physics.

pip install ferrotherm

State a problem in the vocabulary of the problem

Not a QUBO matrix. Variables have names and domains, constraints say what they mean, and the answer comes back keyed by the names you used.

import ferrotherm as ft

p = ft.Problem()
a = p.categorical("a", 3)
b = p.categorical("b", 3)
p.not_equal(a, b)
p.maximize(3 * a.is_(1) + 4 * b.is_(2))

ans = p.solve(tries=32)
print(ans.values)      # {'a': 1, 'b': 2}
print(ans.feasible)    # True

A constraint can be soft — a price rather than a wall — and the answer reports what it cost:

import ferrotherm as ft

p = ft.Problem()
x = p.categorical("x", 3)
y = p.categorical("y", 3)
p.not_equal(x, y, soft=2.0)     # breaking this costs 2.0 x amount squared
ans = p.solve(tries=32)
print(ans.soft_cost, ans.violated)

Or sample the physics directly

import ferrotherm as ft

s = ft.lattice2d(64, 1.0, beta=0.6)   # a magnet below critical temperature
s.sweep(2000)
print(f"|M| = {abs(s.magnetization):.4f}")        # 0.9736
print(f"Onsager = {ft.onsager(0.6):.4f}")         # 0.9736 — the closed form, matched to 4 dp

That second line is the check that matters: Onsager's 1944 closed form for the infinite 2D lattice, and a 64x64 sampler reproducing it to four decimals. The size is not decoration — 16x16 over 500 sweeps gives 0.898 against 0.974, because a small lattice sampled briefly is not the thermodynamic limit. Verify against exact physics before opinions.

ft.ring, ft.z1_grid, ft.frustrated and ft.wishart build the other standard graphs, and ft.Model takes an explicit edge list when you want to write the couplings yourself.

Every run carries its joules

The ledger is not an appendix. A sampler counts the work it did and prices it at Z1-class device figures, so the energy question is answerable rather than rhetorical. Note what is being priced: the modelled device, not the CPU this ran on.

import ferrotherm as ft

s = ft.lattice2d(64, 1.0, beta=0.6)
s.sweep(2000)
print(f"{s.node_updates} node updates -> {s.joules:.2e} J")

The library it binds

This package carries no solver of its own — it loads the shared library and calls it. In order:

  1. FERROTHERM_LIB, if you set it. An explicit path always wins.
  2. The copy shipped in the wheel.
  3. target/release/ of a checkout, for developing against a local build.

ft.library_path() tells you which one answered.

Apache-2.0. Source, the Rust crate and eight other bindings: https://github.com/dcharlot-physicalai-bmi/ferrotherm. From the Institute for Physical AI @ BMI.

Metadata

Release files for ferrotherm 0.42.0

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ferrotherm-0.42.0-py3-none-macosx_11_0_arm64.whl Python 3 none macOS 11.0+ ARM64 Details

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