FoxMath 🦊

Minimalist CLI for math & cryptography exploration.

More about me / other projects: abhrankan.netlify.app

One binary. Clean output. Zero footguns. Educational by design.

Built with curiosity — for students, tinkerers, and crypto/math enthusiasts.

Features

• Legendre symbol
• Modular square root via Tonelli-Shanks (sqrtmod)
• Deterministic Miller-Rabin primality test (isprime)
• Prime factorization via Pollard's rho & trial division (factor)
• Extended Euclidean algorithm (egcd) & Bézout coefficients
• Modular multiplicative inverse (modinv)
• Euler/Hermann Machin-like π approximation
• Elliptic curve point addition (over finite fields), including named curves (secp256k1) with on-curve result validation
• Elliptic curve scalar multiplication k·P (double-and-add), including the point at infinity as a first-class result
• Chinese Remainder Theorem solver (handles non-coprime moduli)
• Continued fraction expansion and convergents
• Challenge/quiz mode — practice problems with scoring, or a worksheet mode for self-study
• Symlink-friendly (foxmath-legendre, foxmath-sqrtmod, foxmath-isprime, foxmath-factor, foxmath-egcd, foxmath-modinv, foxmath-pi, foxmath-ecadd, foxmath-ecmul, foxmath-crt, foxmath-cf, foxmath-challenge)
• JSON output mode

Installation

pip install foxmath

Or from source:

git clone https://github.com/Abhrankan-Chakrabarti/foxmath.git
cd foxmath
pip install -e .

Check which version you have installed:

foxmath --version

foxmath 0.10.0

Usage Examples

foxmath factor 360

360 = 2^3 * 3^2 * 5

foxmath isprime 104729

104729 is prime

foxmath isprime 561

561 is composite

foxmath pi --terms 200

π ≈ 3.1415926535897932384626433832795028841971693993752  (200 terms)

foxmath legendre 5 17

Legendre (5/17) = -1

foxmath sqrtmod 10 13

sqrt(10) = +/-7 (mod 13)

sqrtmod uses the Tonelli-Shanks algorithm to find modular square roots when they exist. It reports an error when the input is a quadratic non-residue modulo the given odd prime.

foxmath egcd 30 50

gcd(30, 50) = 10 = 30*(2) + 50*(-1)

foxmath modinv 3 11

3^-1 ≡ 4 (mod 11)

# Symlinks (optional)
foxmath-ecadd --x1 1 --y1 2 --x2 3 --y2 4 --p 17

Result point: (14, 2)

# Named curve (secp256k1) — computes 2G by default
foxmath ecadd --curve secp256k1

Result point: (89565891926547004231252920425935692360644145829622209833684329913297188986597, 12158399299693830322967808612713398636155367887041628176798871954788371653930)
  ✓ on curve

# Scalar multiplication — same curves, O(log k) double-and-add
foxmath ecmul --curve toy193 --k 7

Result point: (66, 24)
  ✓ on curve

# toy193: y² = x³ + x + 5 (mod 193), #E = 193 (prime) — small enough to
# hand-verify, structured exactly like secp256k1. G = (1, 59).
# k = 0 or a multiple of the group order lands on the identity:
foxmath ecmul --curve toy193 --k 193

Result: point at infinity (identity)

# Chinese Remainder Theorem
foxmath crt --r 2 3 2 --m 3 5 7

x ≡ 23 (mod 105)

# Continued fraction expansion + convergents
foxmath cf --num 355 --den 113

[3; 7, 16]
  3/1
  22/7
  355/113

# Challenge/quiz mode — worksheet (no prompting)
foxmath challenge --topic legendre --count 2 --seed 1 --reveal

1. Legendre symbol (10/13)
   Answer: 1
2. Legendre symbol (3/7)
   Answer: -1

# Baby-size discrete log: given G and Q = k·G, recover k.
# Easy at this scale — the same problem at secp256k1's ~10^77 is why ECDSA works.
foxmath challenge --topic ecdlp --count 1 --seed 9 --reveal

1. On y² = x³ + 1x + 5 (mod 193) with G = (1, 59): find k (2 ≤ k ≤ 20) such that k·G = (60, 171)
   Answer: 16

Drop --reveal to answer interactively instead, with scoring at the end. --topic accepts legendre, crt, ecdlp, sqrtmod, factor, or mixed (default).

# JSON output
foxmath pi --terms 100 --json

{
  "tool": "foxmath",
  "command": "pi",
  "terms": 100,
  "approx": "3.1415926535897932384626433832795028841971693993752"
}

Why FoxMath?

Because math and cryptography are more fun when you can play with them instantly in the terminal — with the same reliability as FoxPipe and fox-vault.

Simple. Practical. Reliable.

License

MIT © Abhrankan Chakrabarti

Star if you find it useful! Issues and PRs welcome.