Package Includes

func_timeout

This is the function wherein you pass the timeout, the function you want to call, and any arguments, and it runs it for up to #timeout# seconds, and will return/raise anything the passed function would otherwise return or raise.

def func_timeout(timeout, func, args=(), kwargs=None):

‘’’

func_timeout - Runs the given function for up to #timeout# seconds.

Raises any exceptions #func# would raise, returns what #func# would return (unless timeout is exceeded), in which case it raises FunctionTimedOut

@param timeout <float> - Maximum number of seconds to run #func# before terminating

@param func <function> - The function to call

@param args <tuple> - Any ordered arguments to pass to the function

@param kwargs <dict/None> - Keyword arguments to pass to the function.

@raises - FunctionTimedOut if #timeout# is exceeded, otherwise anything #func# could raise will be raised

@return - The return value that #func# gives

‘’’

FunctionTimedOut

Exception raised if the function times out

Example

So, for esxample, if you have a function “doit(‘arg1’, ‘arg2’)” that you want to limit to running for 5 seconds, with func_timeout you can call it like this:

from func_timeout import func_timeout, FunctionTimedOut

…

try:

doitReturnValue = func_timeout(5, doit, args=(‘arg1’, ‘arg2’))

except FunctionTimedOut:

print ( “doit(‘arg1’, ‘arg2’) could not complete within 5 seconds and was terminated.n”)

except Exception as e:

# Handle any exceptions that doit might raise here

How it works

func_timeout will run the specified function in a thread with the specified arguments until it returns, raises an exception, or the timeout is exceeded. If there is a return or an exception raised, it will be returned/raised as normal.

If the timeout has exceeded, the “FunctionTimedOut” exception will be raised in the context of the function being called, as well as from the context of “func_timeout”. You should have your function catch the “FunctionTimedOut” exception and exit cleanly if possible. Every 2 seconds until your function is terminated, it will continue to raise FunctionTimedOut. The terminating of the timed-out function happens in the context of the thread and will not block main execution.

Support

I’ve tested func_timeout with python 2.7, 3.4, and 3.5. It should work on other versions as well.

ChangeLog can be found at https://raw.githubusercontent.com/kata198/func_timeout/master/ChangeLog

Pydoc can be found at: http://htmlpreview.github.io/?https://github.com/kata198/func_timeout/blob/master/doc/func_timeout.html?vers=1