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A Jupyter/IPYthon cell based memory and CPU profiler

Project description

ipython_memory_usage

CURRENT SITUATION - Ian is updating this, so this README is probably out of date, only this first section is actually correct as of 2023-11-24

IPython tool to report memory usage deltas for every command you type. If you are running out of RAM then use this tool to understand what's happening. It also records the time spent running each command.

This tool helps you to figure out which commands use a lot of RAM and take a long time to run, this is very useful if you're working with large numpy matrices. In addition it reports the peak memory usage whilst a command is running which might be higher (due to temporary objects) than the final RAM usage. Built on @fabianp's memory_profiler.

As a simple example - make 10,000,000 random numbers, report that it costs 76MB of RAM and took 0.3 seconds to execute:

# %load_ext ipython_memory_usage
# %imu_start
In [3]: arr=np.random.uniform(size=int(1e7))
'arr=np.random.uniform(size=int(1e7))' used 76.2578 MiB RAM in 0.33s, peaked 0.00 MiB above current, total RAM usage 107.37 MiB

Francesc Alted has a fork with more memory delta details, see it here: https://github.com/FrancescAlted/ipython_memwatcher

For a demo using numpy and Pandas take a look at examples/example_usage_np_pd.ipynb.

Setup

Supported: Python 3.8+ and IPython 7.9+

Simple:

$ pip install ipython_memory_usage

via https://pypi.org/project/ipython-memory-usage/

$ conda install -c conda-forge ipython_memory_usage

via https://anaconda.org/conda-forge/ipython_memory_usage

OR

Take a copy of the code or fork from https://github.com/ianozsvald/ipython_memory_usage and then:

$ python setup.py install

If you pull it from github and you want to develop on it, it is easier to make a link in site-packages and develop it locally with:

$ python setup.py develop 

To uninstall:

$ pip uninstall ipython_memory_usage

Example usage

We can measure on every line how large array operations allocate and deallocate memory:

using with magic:

$ ipython
In [1]: import ipython_memory_usage 
# note that help(ipython_memory_usage) will give you some clues
In [1] %ipython_memory_usage_start                                                                                 

Out[1]: 'memory profile enabled'
In [1] used 0.2383 MiB RAM in 0.11s, peaked 0.00 MiB above current, total RAM usage 47.64 MiB

In [2]: import numpy as np 
...: a = np.ones(int(1e7))                                                                                       
In [2] used 85.9180 MiB RAM in 0.22s, peaked 0.00 MiB above current, total RAM usage 133.56 MiB

In [3]: %ipython_memory_usage_stop                                                                                  
Out[3]: 'memory profile disabled'

In [4]: a = np.ones(int(1e7))  

using with function call:

$ ipython
Python 3.4.3 |Anaconda 2.3.0 (64-bit)| (default, Jun  4 2015, 15:29:08) 
IPython 3.2.0 -- An enhanced Interactive Python.

In [1]: import ipython_memory_usage.ipython_memory_usage as imu
In [2]: import numpy as np

In [3]: imu.start_watching_memory()
In [3] used 0.0469 MiB RAM in 7.32s, peaked 0.00 MiB above current, total RAM usage 56.88 MiB

In [4]: a = np.ones(int(1e7))
In [4] used 76.3750 MiB RAM in 0.14s, peaked 0.00 MiB above current, total RAM usage 133.25 MiB

In [5]: del a
In [5] used -76.2031 MiB RAM in 0.10s, total RAM usage 57.05 MiB

In [6]: imu.stop_watching_memory()

In [7]: b = np.ones(int(1e7))

In [8]: b[0] * 5.0
Out[8]: 5.0

For the beginner with numpy it can be easy to work on copies of matrices which use a large amount of RAM. The following example sets the scene and then shows an in-place low-RAM variant.

First we make a random square array and modify it twice using copies taking 2.3GB RAM:

In [1]: imu.start_watching_memory()
In [2]: a = np.random.random((int(1e4),int(1e4)))
In [2] used 762.9531 MiB RAM in 2.21s, peaked 0.00 MiB above current, total RAM usage 812.30 MiB

In [3]: b = a*2
In [3] used 762.9492 MiB RAM in 0.51s, peaked 0.00 MiB above current, total RAM usage 1575.25 MiB

In [4]: c = np.sqrt(b)
In [4] used 762.9609 MiB RAM in 0.91s, peaked 0.00 MiB above current, total RAM usage 2338.21 MiB

Now we do the same operations but in-place on a, using 813MB RAM in total:

In [2]: a = np.random.random((int(1e4),int(1e4)))
In [2] used 762.9531 MiB RAM in 2.21s, peaked 0.00 MiB above current, total RAM usage 812.30 MiB
In [3]: a *= 2
In [3] used 0.0078 MiB RAM in 0.21s, peaked 0.00 MiB above current, total RAM usage 812.30 MiB
In [4]: a = np.sqrt(a, out=a)
In [4] used 0.0859 MiB RAM in 0.71s, peaked 0.00 MiB above current, total RAM usage 813.46 MiB

Lots of numpy functions have in-place operations that can assign their result back into themselves (see the out argument): http://docs.scipy.org/doc/numpy/reference/ufuncs.html#available-ufuncs

If we make a large 1.5GB array of random integers we can sqrt in-place using two approaches or assign the result to a new object b which doubles the RAM usage:

In [2]: a = np.random.randint(low=0, high=5, size=(10000, 20000))
In [2] used 1525.8984 MiB RAM in 6.51s, peaked 0.00 MiB above current, total RAM usage 1575.26 MiB

In [3]: a = np.sqrt(a)
In [3] used 0.097 MiB RAM in 1.53s, peaked 1442.92 MiB above current, total RAM usage 1576.21 MiB

In [4]: a = np.sqrt(a, out=a)
In [4] used 0.0234 MiB RAM in 0.51s, peaked 0.00 MiB above current, total RAM usage 1575.44 MiB

In [5]: b = np.sqrt(a)
In [5] used 1525.8828 MiB RAM in 1.27s, peaked 0.00 MiB above current, total RAM usage 3101.32 MiB

Newer versions of Numpy use temporary objects which provide memory optimisation, see https://docs.scipy.org/doc/numpy-1.13.0/release.html

We see this behaviour in the output below. Prior to version 1.13 we would see a peak memory greater than 0.00MiB above current. Older versions of Numpy and Windows will precipitate differing memory usage due to temporary matrices.

In [2]: a = np.ones(int(1e8)); b = np.ones(int(1e8)); c = np.ones(int(1e8))
In [2] used 2288.8750 MiB RAM in 1.02s, peaked 0.00 MiB above current, total RAM usage 2338.06 MiB

In [3]: d = a * b + c
In [3] used 762.9453 MiB RAM in 0.71s, peaked 0.00 MiB above current, total RAM usage 3101.01 MiB

Knowing that a temporary is created, we can do an in-place operation instead for the same result but a lower overall RAM footprint:

In [2]: a = np.ones(int(1e8)); b = np.ones(int(1e8)); c = np.ones(int(1e8))
In [2] used 2288.8750 MiB RAM in 1.02s, peaked 0.00 MiB above current, total RAM usage 2338.06 MiB

In [3]: d = a * b
In [3] used 762.9453 MiB RAM in 0.49s, peaked 0.00 MiB above current, total RAM usage 3101.00 MiB

In [4]: d += c
In [4] used 0.0000 MiB RAM in 0.25s, peaked 0.00 MiB above current, total RAM usage 3101.00 MiB

For more on this example see Tip at http://docs.scipy.org/doc/numpy/reference/ufuncs.html#available-ufuncs .

Important RAM usage note

It is much easier to debug RAM situations with a fresh IPython shell. The longer you use your current shell, the more objects remain inside it and the more RAM the Operating System may have reserved. RAM is returned to the OS slowly, so you can end up with a large process with plenty of spare internal RAM (which will be allocated to your large objects), so this tool (via memory_profiler) reports 0MB RAM usage. If you get confused or don't trust the results, quit IPython and start a fresh shell, then run the fewest commands you need to understand how RAM is added to the process.

Experimental perf stat report to monitor caching

I've added experimental support for the perf stat tool on Linux. To use it make sure that perf stat runs at the command line first. Experimental support of the cache-misses event is enabled in this variant script (to use this cd src/ipython_memory_usage first):

Python 3.4.3 |Anaconda 2.3.0 (64-bit)| (default, Jun  4 2015, 15:29:08) 
IPython 3.2.0 -- An enhanced Interactive Python.
In [1]: %run -i ipython_memory_usage_perf.py
In [2]: start_watching_memory()

Here's an example that builds on the previous ones. We build a square matrix with C ordering, we also need a 1D vector of the same size:

In [3]: ones_c = np.ones((int(1e4),int(1e4)))
In [4]: v = np.ones(int(1e4))

Next we run %timeit using all the data in row 0. The data will reasonably fit into a cache as v.nbytes == 80000 (80 kilobytes) and my L3 cache is 6MB. The report perf value for cache-misses averages to 8,823/second shows an average of 8k cache misses per seconds during this operation (followed by all the raw sampled events for reference). %timeit shows that this operation cost 14 microseconds per loop:

In [5]: %timeit v * ones_c[0, :]
run_capture_perf running: perf stat --pid 4978 --event cache-misses -I 100
100000 loops, best of 3: 14.9 µs per loop
In [6] used 0.1875 MiB RAM in 6.27s, peaked 0.00 MiB above current, total RAM usage 812.54 MiB
perf value for cache-misses averages to 8,823/second, raw samples: [6273.0, 382.0, 441.0, 1103.0, 632.0, 1314.0, 180.0, 451.0, 189.0, 540.0, 159.0, 1632.0, 285.0, 949.0, 408.0, 79.0, 448.0, 1167.0, 505.0, 350.0, 79.0, 172.0, 683.0, 2185.0, 1151.0, 170.0, 716.0, 2224.0, 572.0, 1708.0, 314.0, 572.0, 21.0, 209.0, 498.0, 839.0, 955.0, 233.0, 202.0, 797.0, 88.0, 185.0, 1663.0, 450.0, 352.0, 739.0, 4413.0, 1810.0, 1852.0, 550.0, 135.0, 389.0, 334.0, 235.0, 1922.0, 658.0, 233.0, 266.0, 170.0, 2198.0, 222.0, 4702.0]

We can run the same code using alternative indexing - for column 0 we get all the row elements, this means we have to fetch the column but it is stored in row-order, so each long row goes into the cache to use just one element. Now %timeit reports 210 microseconds per loop which is an order of magnitude slower than before, on average we have 474k cache misses per second. This column-ordered method of indexing the data is far less cache-friendly than the previous (row-ordered) method.

In [5]: %timeit v * ones_c[:, 0]
run_capture_perf running: perf stat --pid 4978 --event cache-misses -I 100
1000 loops, best of 3: 210 µs per loop
In [5] used 0.0156 MiB RAM in 1.01s, peaked 0.00 MiB above current, total RAM usage 812.55 MiB
perf value for cache-misses averages to 474,771/second, raw samples: [77253.0, 49168.0, 48660.0, 53147.0, 52532.0, 56546.0, 50128.0, 48890.0, 43623.0]

If the sample-gathering happens too quickly then an artifical pause is added, this means that IPython can pause for a fraction of a second which inevitably causes cache misses (as the CPU is being using and IPython is running an event loop). You can witness the baseline cache misses using pass:

In [9]: pass
run_capture_perf running: perf stat --pid 4978 --event cache-misses -I 100
PAUSING to get perf sample for 0.3s
In [9] used 0.0039 MiB RAM in 0.13s, peaked 0.00 MiB above current, total RAM usage 812.57 MiB
perf value for cache-misses averages to 131,611/second, raw samples: [14111.0, 3481.0]

NOTE that this is experimental, it is only known to work on Ian's laptop using Ubuntu Linux (perf doesn't exist on Mac or Windows). There are some tests for the perf parsing code, run nosetests perf_process.py to confirm these work ok and validate with your own perf output. I'm using perf version 3.11.0-12. Inside perf_process.py the EVENT_TYPE can be substituted to other events like stalled-cycles-frontend (exit IPython and restart to make sure the run-time is good - this code is hacky!).

To trial the code run $ python perf_process.py, this is useful for interactive development.

Requirements

Tested on

  • IPython 7.9 with Python 3.7 on OS X 10.14.6 (2019-11)
  • IPython 7.9 with Python 3.8 on Windows 64bit (2019-11)
  • IPython 7.9 with Python 3.7 on Windows 64bit (2019-11)
  • IPython 3.6 with Python 3.6 on Linux 64bit and Macs (2018-04)
  • IPython 3.2 with Python 3.4 on Linux 64bit (2015-06)

Developer installation notes

Ian's 2023 update

conda create -n ipython_memory_usage python=3.12
conda activate ipython_memory_usage
pip install numpy
pip install ipython

pip install -e . # editable installation

ipython
import ipython_memory_usage
%ipython_memory_usage_start

python -m build # builds an installable

Questions:

These notes are for the Man AHL 2019 Hackathon.

conda create -n hackathon_ipython_memory_usage python=3.7
conda activate hackathon_ipython_memory_usage
conda install ipython numpy memory_profiler

mkdir hackathon_ipython_memory_usage
cd hackathon_ipython_memory_usage/
git clone git@github.com:ianozsvald/ipython_memory_usage.git

# note "develop" and not the usual "install" here, to make the local folder editable!
python setup.py develop 

# now run ipython and follow the examples from further above in this README
# make a development environment
$ mkdir ipython_memory_usage_dev
$ cd ipython_memory_usage_dev/
$ conda create -n ipython_memory_usage_dev python=3.9 ipython jupyter memory_profiler numpy pandas
$ conda activate ipython_memory_usage_dev
git clone git@github.com:ianozsvald/ipython_memory_usage.git

# note "develop" and not the usual "install" here, to make the local folder editable!
$ python setup.py develop 

# now run ipython and follow the examples from further above in this README

Acknowledgements

Many thanks to https://github.com/manahl/ for hosting their 2019-11 hackathon. Here we removed old Python 2.x code, added an IPython magic, validated that Python 3.8 is supported and (very nearly) have a working conda recipe. Thanks to my colleagues:

Many thanks to https://github.com/manahl/ for hosting a hackathon (2018-04) that led to us publishing ipython_memory_usage to PyPi: https://pypi.org/project/ipython-memory-usage/ . Props to my colleagues for helping me fix the docs and upload to PyPI:

TO FIX

  • merge perf variation into the main variation as some sort of plugin (so it doesn't interfere if per not installed or available)
  • possibly try to add a counter for the size of the garbage collector, to see how many temp objects are made (disable gc first) on each command?

Problems

  • I can't figure out how to hook into live In prompt (at least - I can for static output, not for a dynamic output - see the code and the commented out blocks referring to watch_memory_prompt)
  • python setup.py develop will give you a sym-link from your environment back to this development folder, do this if you'd like to work on the project

Notes to Ian

To push to PyPI I need to follow https://packaging.python.org/en/latest/tutorials/packaging-projects/:

  • pip install -U twine
  • python -m build
  • python -m twine upload --repository testpypi dist/*

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