Simple linear prediction - fit y = mx + c and predict values
Project description
LinPredict
Simple linear prediction library. Pass x and y values, get the next predicted value.
Installation
pip install linpredict
Quick Start
from linpredict import quick_predict, fit, predict_next
# Simplest usage - just pass y values
predictions = quick_predict([2, 4, 6, 8])
print(predictions) # [10.0]
# Predict multiple steps ahead
predictions = quick_predict([2, 4, 6, 8], steps=3)
print(predictions) # [10.0, 12.0, 14.0]
Full Usage
from linpredict import fit, predict_next
# Fit a line to your data
x = [1, 2, 3, 4, 5]
y = [2.1, 3.9, 6.2, 7.8, 10.1]
# Get the line equation
eq = fit(x, y)
print(eq) # y = 1.9900x + 0.0600
# Access slope and intercept
print(f"Slope: {eq.slope}") # ~2.0
print(f"Intercept: {eq.intercept}") # ~0.0
# Predict specific x values
print(eq.predict(6)) # Single prediction
print(eq.predict([6, 7, 8])) # Multiple predictions
# Or use predict_next for automatic next value
next_x, next_y = predict_next(x, y, steps=2)
print(f"Next x: {next_x}, Next y: {next_y}")
API Reference
fit(x, y) -> LineEquation
Fit a line (y = mx + c) to data points. Returns a LineEquation object.
predict_next(x, y, steps=1) -> (list, list)
Predict the next value(s) in sequence. Returns tuple of (next_x_values, predicted_y_values).
quick_predict(y, steps=1) -> list
Quick prediction when you only have y values (assumes x is 0, 1, 2, ...).
LineEquation
.slope- The m in y = mx + c.intercept- The c in y = mx + c.predict(x)- Predict y for given x value(s)
License
MIT
Author
PRAVIN MR
GitHub: https://github.com/mr-pravin
Email: mrpravin000@gmail.com
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