lungo 0.1.2

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Lungo Programming Language

Lungo is a dynamic programming language created just for fun.

Getting Started

Installations:

pip install --upgrade lungo

Usage:

lungo [FILE]

Syntax

You need to define variable with let statement before assignment/reference:

let x = 2;

Assign a previously defined variable:

let x = 0;
x = 42;

Define a function:

func inc(x) {
    return x + 1
}

The last statement in each code block is a result of the block evaluation, so in the previous example return is not necessary:

func inc(x) {
  x + 1
}

Function definitions are just an expressions. The previous line is equivalent to:

let inc = func(x) { x + 1 }

Conditional execution:

if ( x > 0 ) {
  print("Positive")
} elif ( x < 0 ) {
  print("Negative")
} else {
  print("X is 0")
}

while-loop:

let x = 0;
while ( x < 10 ) {
  x = x + 1;
  print(x)
}

for-loop:

for ( x in [1,2,3] ) {
  print(x)
}

Almost everything is expression in Lungo (except for return and let statements):

let x = 10;
let message = if(x > 5) { "big" } else { "small" };
print(message)

Output:

big

Another example:

func hello(value) {
    print("Hello " + value)
};

let who = "world";

hello(while(who.size < 20) { who = who + " and " + who })

Output:

Hello world and world and world and world

NOTE: A bit of syntactic bitterness. In the current implementation each statement in a code block (except for the last one) must be followed by a semicolon ;. So the ; must be present after such expressions as function definitions, for and while-loops, etc. This will be fixed in a future release.

Supported binary operators: +, -, *, /, &&, ||, ==, !=, >, >=, <, <=

Unary operators: !, -

Higher order functions:

func inc(x) {
  x + 1
};

func comp(f, g) {
  func(x) {
    f(g(x))
  }
}

print(comp(inc, inc)(0))

Output:

2

More sophisticated example:

func pair(a, b) {
    func(acceptor) {
        acceptor(a, b)
    }
};

func first(p) {
    p(func(a,b) { a })
};

func second(p) {
    p(func(a,b) { b })
};

let p = pair(1, 2);

print(first(p));
print(second(p));

Output:

1
2