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the OBSCENE string generation one-liner

Project description

The purpose of the mapjoin function is to have an alternative to str.join that looks more like os.path.join (which takes *args).

mapjoin()

from mapjoin import mapjoin, strjoin

mapjoin('foo', 2)                      # raise TypeError
mapjoin('foo', 2, sep='_', key=str)    # return 'foo_2'

# you can also make mapjoin use your own callback with the key kwarg:
your_formatter = lambda key: str(key) if key else 'Nothin!'
mapjoin('foo', obj, 2, None, sep='\n', key=your_formatter)

strjoin()

strjoin('foo', 2)                      # 'foo-2'
strjoin('foo', 2, sep='_')             # 'foo_2'

But … why ?

Initially, because I make to many mistakes when I write an os.path.join call and then a str.join call in a row:

>>> os.path.join('a', 'b')
'a/b'

# and 2 seconds later i'm doing this:

>>> ' '.join('a', 'b')
TypeError: join() takes exactly one argument (2 given)

# and instead of "just fixit and move on", i decided try to make a joint

But also because I can’t get no satisfaction with my code when it looks like:

readable = ' '.join(map(str, [
    'hello',
    f'__{name}__',
    something,
]))

# or:

def foo():
    readable = textwrap.dedent(f'''
    hello
    __{name}__
    ''').strip()

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