murl 0.5.1

murl is a tiny wrapper for the Python module urlparse.

Project details

Code:

http://github.com/berkerpeksag/murl

Issues:

https://github.com/berkerpeksag/murl/issues/

Documentation:

http://murl.rtfd.org/

Build status:

Installation

Install with pip:

$ pip install murl

Getting Started

Note

Detailed documentation can be found on http://murl.rtfd.org/.

from murl import Url


url = Url('https://bugzilla.mozilla.org/show_bug.cgi?id=698201#c0')
print url.scheme, url.host, url.querystring, url.fragment
# https bugzilla.mozilla.org id=698201 c0

url.scheme = 'http'
url.host = 'bugzilla.webkit.org'

print url
print url.url
print url.scheme
print url.host
print url.netloc
print url.host == url.netloc
# http://bugzilla.webkit.org/show_bug.cgi?id=698201#c0
# http://bugzilla.webkit.org/show_bug.cgi?id=698201#c0
# http
# bugzilla.webkit.org
# bugzilla.webkit.org
# True

url.path = 'list_bugs.cgi'
print url.path, url.url
# list_bugs.cgi http://bugzilla.webkit.org/list_bugs.cgi?id=698201#c0

url.fragment = 'c1'
print url.fragment
print url.url
# c1
# http://bugzilla.webkit.org/list_bugs.cgi?id=698201#c1

url.fragment = ''
print url.fragment
print url.url
# ''
# http://bugzilla.webkit.org/list_bugs.cgi?id=698201

License

All files that are part of this project are covered by the following license, except where explicitly noted.

This Source Code Form is subject to the terms of the Mozilla Public License, v. 2.0. If a copy of the MPL was not distributed with this file, You can obtain one at http://mozilla.org/MPL/2.0/.