Chemical formula parser for Python
Project description
py-parse-formula: Chemical formula parser for Python
Installation
pip install parse-formula
Usage
Basic Usage
By default, it returns int counts. (Only accept stoichiometric compounds)
>>> from parse_formula import parse_formula
>>> parse_formula("CH3CH2CH2CH3")
{'C': 4, 'H': 10}
>>> parse_formula("K4[Fe(CN)6]")
{'K': 4, 'Fe': 1, 'C': 6, 'N': 6}
Handling Non-stoichiometric Compounds (float/Decimal/Fraction)
You can specify the type of the returned counts using the parse_number argument.
>>> from decimal import Decimal
>>> from fractions import Fraction
>>> from parse_formula import parse_formula
>>> parse_formula("Fe0.9O")
parse_formula._parser.FormulaValueError: invalid literal for int() with base 10: '0.9'
Hint: Try calling `parse_formula(..., parse_number=float)`
>>> parse_formula("Fe0.9O", parse_number=float)
{'Fe': 0.9, 'O': 1.0}
>>> parse_formula("Fe0.9O", parse_number=Decimal)
{'Fe': Decimal('0.9'), 'O': Decimal('1')}
>>> parse_formula("Fe0.9O", parse_number=Fraction)
{'Fe': Fraction(9, 10), 'O': Fraction(1, 1)}
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