A password generation utility
passwdgen is a simple password generation utility with a couple of
powerful extra features (including password entropy calculation and
entropy-based password generation).
passwdgen, you will need to install Python 3.6+.
> pip install passwdgen
If you want
passwdgen to be globally accessible, you'll need to
install it with
> sudo pip install passwdgen
The simplest password generation command you can execute is:
> passwdgen generate totems-representing-sachem-tarrier
To find out more detailed help about a particular command, simply run:
> passwdgen <command> --help # For example: > passwdgen generate --help
Allows you to calculate the entropy of a particular password. For example, on UNIX-like systems, you can simply pipe the password into the info command:
> echo "some-password" | passwdgen info > cat /path/to/password/file | passwdgen info
If you do not pipe text into
passwdgen, it will prompt you to enter
the password on the command line:
> passwdgen info Please enter the password to check: <type your password here>
For more information on password entropy, please see the section on Entropy further on in this README.
Generate a password. Two kinds of passwords can be generated:
- dictionary-based passwords (the default), or
- character-based passwords (see this XKCD before you choose this mechanism).
Some examples of dictionary-based password generation:
# Generate a dictionary-based password 6 words long > passwdgen generate -l 6 # Generate a dictionary-based password with minimum entropy 70 bits > passwdgen generate -m 70 # Generate a dictionary-based password and copy it to the clipboard > passwdgen generate -c # Generate a dictionary-based password with colons (:) as a separator > passwdgen generate -s colon # Generate a dictionary-based password and display its entropy info > passwdgen generate -i # Generate a dictionary-based password based on the given starting letters > passwdgen generate --starting-letters hello
Some examples of character-based password generation:
# Generate a password 15 characters long comprising numbers and letters > passwdgen generate -t alpha-numeric -l 15 # Generate a password 18 characters long comprising numbers, letters and # special characters > passwdgen generate -t special -l 18 # Generate a password 12 characters long and display its entropy info > passwdgen generate -t special -l 12 -i # Generate a character-based password, copy it to the clipboard, and # display its entropy info > passwdgen generate -t special -c -i
Runs a quick test of your OS' pseudorandom number generator (PRNG). Computes a sample set (by default, 1 million entries) of random numbers between 0 and 100 (inclusive)
> passwdgen rng Testing OS RNG. Attempting to generate 1000000 samples between 0 and 100 (inclusive). Please wait... Statistics ---------- Mean : 49.966455 (should approach 50.000 as the sample size increases; 0.067% difference) Standard deviation : 29.151161 (should be as close to 29.154759 as possible; 0.012% difference) Time taken : 2.083 seconds
The expected standard deviation for a random variable with a discrete uniform random distribution is expected to be calculated as per this Wikipedia entry.
At present, this command has only one sub-command:
clean. To take
an arbitrary word list (a text file with one word per line) and
clean it up, do the following:
> passwdgen wordlist clean /path/to/input/file.txt /path/to/output/file.txt
This command will:
- remove empty lines,
- strip out any plurals (
'sat the end of strings),
- convert all words to lowercase,
- deduplicate entries, and
- sort everything alphabetically.
passwdgen from your own Python project is easy:
import passwdgen # Generate a dictionary-based password using the built-in dictionary my_password = passwdgen.words() # Generate a character-based password my_password = passwdgen.chars() # Generate a dictionary-based password with 6 words long_password = passwdgen.words(word_count=6) # Generate a dictionary-based password with minimum entropy 80 difficult_password = passwdgen.words(min_entropy=80) # Generate a dictionary-based password with a custom dictionary my_dictionary = passwdgen.load_word_list("/path/to/my/dict.txt") password = passwdgen.words(my_dictionary)
passwdgen.words(dict_set, separator, word_count, min_entropy, starting_letters)
Generates a dictionary-based password. All arguments are keyword arguments and are optional:
setcontaining all of the possible words from which to generate a password. If not supplied, this will default to the built-in dictionary.
separator: The separator character to use between the words. Default value:
word_count: The number of words to use when generating the password. If not specified, and
min_entropyis not specified, this defaults to
min_entropy: The minimum required entropy of the generated password. If
word_countis specified, this parameter is ignored.
starting_letters: A string containing the desired starting letters of each word in the generated password. Note: if
min_entropyare specified, this string must contain at least the relevant number of characters to match the number of generated words. Otherwise the generated password will have exactly the same number of words as this string has characters.
Returns a string.
passwdgen.chars(charset, length, min_entropy)
Generates a character-based password. All arguments are keyword arguments and are optional:
charset: The ID of the character set from which to source characters for the generated password. Default:
special. See the section on Character Sets below.
length: The required number of characters in the generated password. If neither
min_entropyare specified, this defaults to
min_entropy: The minimum required entropy of the generated password. If
lengthis specified, this parameter is ignored.
Returns a string.
Loads a word list into memory. All arguments are keyword arguments and are optional:
filename: The path to the file from which to load the words. This file must be a plain text file containing one word per line. If not specified, this loads the built-in dictionary into memory.
encoding: The character encoding to use when reading the file.
set containing the loaded words.
Securely generates a random number using the given limits.
arepresents the lower limit (inclusive) of the resulting random number. If
bis not specified,
arepresents the upper limit (exclusive) of the generated number, and the lower limit defaults to
b(optional): The upper limit (exclusive) of the generated random number.
Returns a securely generated random number with
a <= result < b if
b is specified, or
0 <= result < a if
b is not specified.
Attempts to calculate the entropy of the given password based on the preconfigured character sets and the dictionary.
password(required): The password whose entropy is to be calculated.
setof words comprising the dictionary for which to perform the dictionary-based entropy calculation.
dict whose keys represent the IDs of the different character
sets tested, and values represent the corresponding entropies.
The following character sets are available at present (for use with the
generate --charset <charset> command).
dict: Dictionary-based password generation.
alpha-lower: Lowercase alphabetical letters (
alpha-upper: Uppercase alphabetical letters (
alpha: Alphabetical (
alpha-numeric: Alphanumeric characters (
alpha-numeric-spaced: Alphanumeric characters and spaces (
numeric: Numeric characters (
alpha-lower-sep: Lowercase alphabetical letters and separators (
alpha-upper-sep: Uppercase alphabetical letters and separators (
special: Alphanumeric characters and special characters (
Entropy, in the context of information theory, provides a convenient way to quantify the amount of information in a particular set of data. With regard to password strength, the higher the entropy of a password, the more difficult it is for an attacker to guess.
From the perspective of the generator, the password strength is measured by way of the information source. From the perspective of an attacker, the more information is known about the information source that generated the password (e.g. the kind of random number generator used, the character set to which the password belongs), the lower the entropy of that password.
Secure random number generation
Entropy calculations are based on the assumption that the random number
source is of good quality (see CSPRNG)
and generates uniformly distributed
random numbers. The random number generator (RNG) used in
is provided by the
os.urandom() function, which uses
on POSIX systems and
CryptGenRandom() on Windows systems.
This password generator uses the following definition for entropy: a
c from a character set of size
n characters has
an entropy of
log2(n) bits (per character). Entropy adds up as the
length of the password increases, i.e. two characters from the character
set of size
n will have a combined overall entropy of
2 x log2(n).
For example, if the lowercase alphabet
a..z is used as the character
set, it has
n=26. Each character would have an entropy of
log2(26) = 4.700439718141093 bits per character. A password string,
therefore, such as
mysuperweakpassword of length 19 characters, will
have a total entropy of
19 x log2(26) = 89.31 bits.
As the size of the character set increases, so does the entropy of the password of a certain length, as an attacker attempting a brute force attack would have to search a much larger set of possibilities to find the password.
The dictionary-based method of entropy calculation assumes that an
attacker has prior knowledge that the password was generated using a
dictionary of words, and even knows which dictionary was used. This
would obviously be the case if you personally used
generate a dictionary-based password, as all the code and the dictionary
are out in the open.
In this case, instead of assuming a character set (which would mean a far higher entropy in passwords with 2 or more words), a dictionary-based attack could be performed much quicker.
For example, the password
dog-far-nightly-can is 19 characters long
and makes use of the lowercase alphabet and hyphens (resulting in a
character set of 27 possible characters). This means that a
brute force attacker using the full lowercase alphabet and hyphens
would be faced with a potential password entropy of
19 x log2(27) = 90.34 bits.
If, however, the attacker knows that the password is dictionary-based
and that the words are separated by hyphens, the attacker would only
have to guess the 4 words from the dictionary making up the password.
This results in a potential entropy from the perspective of the
4 x log2(275,185) = 72.28 bits (assuming dictionary
size of 275,185 words). This is still a pretty strong password, but
it is still easier to crack than a password where the attacker does not
know that it is dictionary-based.
How much entropy is enough?
So how does one select an appropriate entropy for trying to prevent brute force attacks? This is difficult to estimate, because it depends entirely on the resources available to an attacker. Usually it's cheaper and easier to perform social engineering attacks if someone wants to obtain your password, but if you're paranoid about security and want to cover all your bases, you have to think about the kinds of computing power available to attackers.
Assuming that whichever service stores your password does not store the clear password itself, but a SHA-256 hash of the password (common practice today), and an attacker manages to get hold of this SHA-256 hash, they will have to try many possible permutations of input passwords that will eventually match to that SHA-256 hash.
In general, GPU-based hash attacks are much faster
than CPU-based hash attacks. At the time of this writing, it would seem
as though high-end GPUs have the ability to perform around 1,000
megahashes per second (that's 1,000,000,000 hashes per second, or
10^9 hashes per second).
Let's assume you generate a dictionary-based password, where the source dictionary size is 71,188 words. Let's also assume that the attacker has the same source dictionary, and knows which character you use to separate the words in your password (in this case, a hyphen).
|Words||Permutations||Time to Crack||Entropy|
|2||5,067,660,156||5.07 seconds||32.24 bits|
|3||360,746,455,865,016||4.175 days||48.36 bits|
|4||25,679,736,460,751,163,960||814 years||64.47 bits|
|5||1,827,986,360,222,110,855,328,640||57,965,067 years||80.6 bits|
Of course, if an attacker splits the work up evenly across multiple GPUs, the time to crack goes down linearly, so a 4-word password being brute-force cracked by 2 GPUs would take 407 years, 3 GPUs would take 203.5 years, 10 GPUs 81.4 years, 100 GPUs 8.1 years, 1,000 GPUs would take about 9.5 months, and 10,000 GPUs would take 29.7 days.
So, as you see, it really depends on the resources available to an attacker. In general though, right now, a password with entropy 80 bits and upwards, from the perspective of an attacker, is pretty much infeasible to crack (so a 5-word password from a significantly sized source dictionary and a good quality PRNG). This will, of course, possibly change in the age of quantum computers.
At present, the embedded dictionary contains 71,188 words, ensuring
an entropy of
log2(71,188) = 16.119 bits per word.
Copyright 2000-2014 by Kevin Atkinson
Permission to use, copy, modify, distribute and sell these word lists, the associated scripts, the output created from the scripts, and its documentation for any purpose is hereby granted without fee, provided that the above copyright notice appears in all copies and that both that copyright notice and this permission notice appear in supporting documentation. Kevin Atkinson makes no representations about the suitability of this array for any purpose. It is provided "as is" without express or implied warranty.
Copyright (c) J Ross Beresford 1993-1999. All Rights Reserved.
The following restriction is placed on the use of this publication: if The UK Advanced Cryptics Dictionary is used in a software package or redistributed in any form, the copyright notice must be prominently displayed and the text of this document must be included verbatim.
There are no other restrictions: I would like to see the list distributed as widely as possible.
Many sources were used in the creation of SCOWL, most of them were in the public domain or used indirectly. For a full list please see the SCOWL readme.
The following sources were consulted in building the password generator:
- Entropy (information theory) ~ Wikipedia
- How should I calculate the entropy of a password? ~ Cryptography StackExchange
- How to calculate password entropy
- Permutation ~ Wikipedia
The MIT License (MIT)
Copyright (c) 2016 Thane Thomson
Permission is hereby granted, free of charge, to any person obtaining a copy of this software and associated documentation files (the "Software"), to deal in the Software without restriction, including without limitation the rights to use, copy, modify, merge, publish, distribute, sublicense, and/or sell copies of the Software, and to permit persons to whom the Software is furnished to do so, subject to the following conditions:
The above copyright notice and this permission notice shall be included in all copies or substantial portions of the Software.
THE SOFTWARE IS PROVIDED "AS IS", WITHOUT WARRANTY OF ANY KIND, EXPRESS OR IMPLIED, INCLUDING BUT NOT LIMITED TO THE WARRANTIES OF MERCHANTABILITY, FITNESS FOR A PARTICULAR PURPOSE AND NONINFRINGEMENT. IN NO EVENT SHALL THE AUTHORS OR COPYRIGHT HOLDERS BE LIABLE FOR ANY CLAIM, DAMAGES OR OTHER LIABILITY, WHETHER IN AN ACTION OF CONTRACT, TORT OR OTHERWISE, ARISING FROM, OUT OF OR IN CONNECTION WITH THE SOFTWARE OR THE USE OR OTHER DEALINGS IN THE SOFTWARE.
Release history Release notifications | RSS feed
Download the file for your platform. If you're not sure which to choose, learn more about installing packages.
|Filename, size||File type||Python version||Upload date||Hashes|
|Filename, size passwdgen-0.3.1-py3-none-any.whl (212.3 kB)||File type Wheel||Python version py3||Upload date||Hashes View|
|Filename, size passwdgen-0.3.1.tar.gz (219.4 kB)||File type Source||Python version None||Upload date||Hashes View|
Hashes for passwdgen-0.3.1-py3-none-any.whl