py-exceptions 1.2.2

A simple python exception reporter

py-exceptions

A simple python exception reporter

Description

This library provides great stacktrace and web request information like Django does It can save it to html, return html to your code or even response in AWS lambda format

The library nicely covers all your secret variables and request data in its report

Screenshots

Quickstart

Installation

pip install py-exception

Simple example

Add decorator to function

from pyexceptions import handle_exceptions


def divide(a, b):
    return a / b


@handle_exceptions
def main():
    i = 5
    j = 0
    c = divide(i, j)
    print(c)


if __name__ == '__main__':
    main()

You can also override folder for exception reports

from pyexceptions import handle_exceptions


def divide(a, b):
    return a / b


@handle_exceptions(exceptions_folder=f'./SomeFolderPath')
def main():
    i = 5
    j = 0
    c = divide(i, j)
    print(c)


if __name__ == '__main__':
    main()

AWS Lambda example

It is hard to determine what's went wrong when you are using AWS lambda. So you can use the example not only to get full stacktrace but to get lambda event and context information:

from pyexceptions import handle_exceptions


@handle_exceptions(is_lambda=True)
def lambda_handler(event, context):
    message = f"Hello {event['first_name']} {event['last_name']}!"
    return {
        'message': message
    }

Exclude from stacktrace

There may be situations when you don't want to see part of stacktrace

So if your application looks like this:

from pyexceptions import handle_exceptions

def divide(a, b):
    return a / b

def real_main():
    i = 5
    j = 0
    c = divide(i, j)
    print(c)

def wrapper():
    real_main()

@handle_exceptions(exclude = 3)
def main():
    wrapper()

if __name__ == '__main__':
    main()

and you want to exclude all stacktrace from main to wrapper you need to pass file_name.function_name as exclude argument

Other functions

You can also want to use these functions:

Make function that returns HTML and don't save the result:

from pyexceptions import handle_exceptions


@handle_exceptions(save=False)
def main():
    ...

Make function return production html:

from pyexceptions import handle_exceptions


@handle_exceptions(production=True)
def main():
    ...

Or you may want to write your own logic To do so you need to import the ExceptionHandler class

from pyexceptions import ExceptionHandler

That's how it looks like:

class ExceptionHandler:
    """Organize and coordinate reporting on exceptions."""

    def __init__(self, lambda_event: dict = None, context: object = None, exclude: int = 1, production: bool = False):
        """Exception reporter initializer

        Args:
            lambda_event (dict, optional): AWS lambda event. Defaults to None.
            context (object, optional): AWS lambda context. Defaults to None.
            exclude (int, optional): Determines how many frames of traceback to exclude. Defaults None.
            production (bool, optional): Determines if handler should be enabled. Defaults False.
        """
        self.__reporter = ExceptionReporter(lambda_event=lambda_event, context=context, exclude=exclude, # noqa
                                            production=production)

    def get_traceback_html(self):
        """Return HTML version of debug 500 HTTP error page."""
        return self.__reporter.get_traceback_html()

    def get_traceback_lambda(self):
        """Return AWS lambda version of debug 500 HTTP error page."""
        return self.__reporter.get_lambda_response()

Attribution

This implementation draws upon work from:

• Django

• vercel-python-wsgi