pycurl 7.43.0.1

PycURL -- A Python Interface To The cURL library

PycURL is a Python interface to libcurl, the multiprotocol file transfer library. Similarly to the urllib Python module, PycURL can be used to fetch objects identified by a URL from a Python program. Beyond simple fetches however PycURL exposes most of the functionality of libcurl, including:

• Speed - libcurl is very fast and PycURL, being a thin wrapper above libcurl, is very fast as well. PycURL was benchmarked to be several times faster than requests.

• Features including multiple protocol support, SSL, authentication and proxy options. PycURL supports most of libcurl’s callbacks.

• Multi and share interfaces.

• Sockets used for network operations, permitting integration of PycURL into the application’s I/O loop (e.g., using Tornado).

Requirements

• Python 2.6, 2.7 or 3.1 through 3.6.

• libcurl 7.19.0 or better.

Installation

Download source and binary distributions from PyPI or Bintray. Binary wheels are now available for 32 and 64 bit Windows versions.

Please see the installation documentation for installation instructions.

Documentation

Documentation for the most recent PycURL release is available on PycURL website.

Support

For support questions please use curl-and-python mailing list. Mailing list archives are available for your perusal as well.

Although not an official support venue, Stack Overflow has been popular with some PycURL users.

Bugs can be reported via GitHub. Please use GitHub only for bug reports and direct questions to our mailing list instead.

License

PycURL is dual licensed under the LGPL and an MIT/X derivative license based on the libcurl license. The complete text of the licenses is available in COPYING-LGPL and COPYING-MIT files in the source distribution.