pyfract 1.3

Fractions implementation for Python

PyFract

A simple implementation of fraction numbers in Python. In some cases it is better than default Python library for fractions.

Instalation

pip install pyfract

Usage

Initialization

from pyfract.fraction import Fraction

f = Fraction(1, 2)
print(f) # [1/2]

f = Fraction(numerator=1, denominator=2)
print(f) # [1/2]

Mathematical operations

You can use all of the math operations with other fraction, int or float as shown in the example below

from pyfract.fraction import Fraction

f1 = Fraction(1, 2)
f2 = Fraction(1, 4)

print(f1 + f2) # [3/4]
print(f1 - f2) # [1/4]
print(f1 * f2) # [1/8]
print(f1 / f2) # [2/1]

print(f1 + 2) # [5/2]
print(f1 - 2) # [-3/2]
print(f1 * 2) # [1/1]
print(f1 / 2) # [1/4]

Comparisons

You can compare fractions using operators like greater than, less than and so on...

from pyfract.fraction import Fraction

f1 = Fraction(1, 2)
f2 = Fraction(1, 4)

print(f1 < f2) # False
print(f1 <= f2) # False
print(f1 > f2) # True
print(f1 >= f2) # True
print(f1 == f2) # False
print(f1 != f2) # True

Conversion from float

from pyfract.fraction import Fraction

print(Fraction.from_float(0.5)) # [1/2]
print(Fraction.from_float(0.134)) # [67/500]

Accurate conversion from float

Fast conversion from float doesn't work so well for float like 0.333333333333333333. This method is much slower, but allows to convert floats more accurately

from pyfract.fraction import Fraction

x = 1 / 3
print(x) # 0.3333333333333333
f = Fraction.from_float_accurately(x)
print(f) # [1/3]

accuracy defines up to how many decimal places the fraction must be accurate. By default it is 8

from pyfract.fraction import Fraction

f = Fraction.from_float_accurately(0.31987398749812214, accuracy=10)
print(f) # [44981/140621]

To float

from pyfract.fraction import Fraction

f = Fraction(1, 2)
print(f.to_float()) # 0.5

Contributing

Make a fork of this repository, clone codebase, create new branch, make your changes, commit it, push to remote, create pull request to this repository. Any contribution highly appreciated