PyIota - Simple Go lang iota pattern implementation

Simple Usage

from pyiota import iota

with iota.start():
  A = iota()
  B = iota()
  C = iota()
with iota.start(10):
  D = iota()
  E = iota()
  F = iota()
print(A, B, C, D, E, F) #=> '0 1 2 10 11 12'

How it works?

0. Default iota._counter value equals to -1.
1. A = iota() - iota.__new__() increments iota._counter and returns it.
2. It is possible to reset iota._counter calling iota() within with iota.start(): ... block.
   2.1. You can also provide a number to start from. For example: D, E and F from example above will be equal to 10, 11, and 12 accrordingly.